New User Special Price Expires in

Let's log you in.

Sign in with Facebook


Don't have a StudySoup account? Create one here!


Create a StudySoup account

Be part of our community, it's free to join!

Sign up with Facebook


Create your account
By creating an account you agree to StudySoup's terms and conditions and privacy policy

Already have a StudySoup account? Login here

Intro Physics II

by: Kylie Bartoletti DVM

Intro Physics II PHYS 2212

Kylie Bartoletti DVM

GPA 3.67

Edwin Greco

Almost Ready


These notes were just uploaded, and will be ready to view shortly.

Purchase these notes here, or revisit this page.

Either way, we'll remind you when they're ready :)

Preview These Notes for FREE

Get a free preview of these Notes, just enter your email below.

Unlock Preview
Unlock Preview

Preview these materials now for free

Why put in your email? Get access to more of this material and other relevant free materials for your school

View Preview

About this Document

Edwin Greco
Class Notes
25 ?




Popular in Course

Popular in Physics 2

This 0 page Class Notes was uploaded by Kylie Bartoletti DVM on Monday November 2, 2015. The Class Notes belongs to PHYS 2212 at Georgia Institute of Technology - Main Campus taught by Edwin Greco in Fall. Since its upload, it has received 11 views. For similar materials see /class/234276/phys-2212-georgia-institute-of-technology-main-campus in Physics 2 at Georgia Institute of Technology - Main Campus.


Reviews for Intro Physics II


Report this Material


What is Karma?


Karma is the currency of StudySoup.

You can buy or earn more Karma at anytime and redeem it for class notes, study guides, flashcards, and more!

Date Created: 11/02/15
161723 a Sun the rod IS posmvely charged much chunk of charge WK JIOdHCE aux electnv eld that pmnts to the right r a v v u L v we ongm to an ubm euy chunk o fame m L4 1 7 I Is the thtance from an arbitrary chunk to he obsemuon locauou Emch chunk produces 21 eld Afar 10 m 21 m C E ig m mtif mid a L u M 16P38 Using IE n vlth IUPJI I 39 L H EcuUR u 0 ummu Megan dmxgndmth Trml 0ch chunk u a pumclv qu talcumquot AP Tlu l UMlIl xs 1 R h A0vcw smlk E n1 um um rouxr mum Inwrud he um mMpuuA m menou hv wuuumry Fm mull wdum U n man H Um eld nppmwchm that of a punch M uxpecm 161342 a As he particle mm the legmn between my plates n mu de ect dmnlwald due b0 ms Interaction wth the eiectnc eld Upon leaving the pL es m trajectory mu m change at w and mu 12min me b At low speeds I a mm 01 a 18x m nus c 39 H Viquot 10 0 Tbs upper plm must be negauvely dxuged given Lhe dmmm of E 161348 0 F 713 E7 F F m m r E P A u A G x 10quot N i a a p 0008kgmm1bll lU mnl 161350 a V b There mu 39 y a wa be midtngch d e T119 net eiectuc ed mm the meLzl is mo so me rhnjge on Its mm sudsce musi be the opposxlze of am on me glass sphele f EF wm be unch a v v L 4 A 39 L thele balloon 1 zero 2 13 x107 Lquot 4 m 003 m gt14 0711 a lt0 7195x105 D NC Em 4 m 2x10 c Zulu moo m 002 21 0012 m z 125 x10UUgtNC a lt125 x 1037195 10gtUgt NC b 5 a 74 x M 1113 meiCl 125 1n 7 95 x 105 NC a 17 x M 111 5 1w 10 quot L 1 N 4 uh 11m LD 0 N 1 X 10 5 I LP GT a See pzu39t b b The protau is m equilibrium m m 11 10 cmm c 71 x w CmNC 1 x10 N a gtlt1E c d e Doubling Che poLanzablhty wuuld halv me spnug su hess 1 71146 Is negauve Thus E poms Lo che nghL Posmbly a E poms wwzu39dlcvwe potenmj B m at law patenhal smce V 442 Is uegahve md A 15 poamve 1f n 15 a cxtpacitcn b where s 7 01m and z A 7 472 3 7 AV 77141 V885 x 1U D W Eli x in m c ESQM7 1le m m then A 7 C V 2 Q mwm EJULORMmJ 273 y 104 C Mm 15 ampammr then 7 u 1 m QA 2w y 1 sud E 7273 x 107 c would produce the given potentan dl arence mxw me planes As long as R gt gt chem ynu can choose any R and solve for Q 171250 nvm n n Vu39nH HA Auchecemzalpmecbeu a AV 7E 1A4 V 472V 704 m m 7290 V If m as from he pm to pom B then AV E XAJN 7 itimlm m V m Tm 15 along a pm from A m B 50 V2 M Aquot gr in 4quot us V 205 V 3 Ali I V K U 5 1 u M AI39 n quotA1 I 1 10quot 7205 V 73 8 IU HJ 1 1m 0 m 13 than A must 1 at least 3128 1047 171362 A picture 139 the Lipolo IS shown in gure at 11 1 Flgm39e x Elecmr penennui m locatmn any due no a deub b Expand he demmmcozs 1 r2J2J39ay2 l Neglect am am since e a at small 5 y g L mn cuyhzs 3 as Note that I 1 7 F mtor out 111 the duuommator Use binomial appmmmiou 1 7 Note am it pomts on uppvsltely dmged pruhclea ALSO r c Along the x axls F0 and y A 13 So 7 i zli asexpected Also 4 39 4 L 14on E Is In 39 L we mien along the m of L dipole W a smce n m pxopoxmoml w r on in 15 case 1d Along my yams 7 n am Thu means um EV n along the yaxjs Thu 12 quot and Me not m sme HE has an It s alemmdm Hm x or z componzu 171365 11 can this Er It 1s positive and poims to the right as expected h 1 m1 2 1m mm c The path should start at B m1 end at C Thka quot nal miti quot d 2 AV 7 471Ade E r AT Le pnsit n so AV E negativa e NfCMJUOD m 7 b 1 8mm 307V J 11 716110 CJ31 7W m J AH A39 U AK 74139 u 47 10quot J 171168 Inside a m3fo ml y E x y a zn av E I 39 n 1 5 eIONegk11 a the helm then M u minds the spine A5 25m r Inside the sphere m cunsmnt mm mm cu m potenbml m we sm fm e mm 5 1 it 1 quot 1 An electron IS maved 1t comm speed om v39 1 391 t to v The belt docs work on like system R Apply me Energy Punclple to me electron and sphere T39hm is posmve as expected 17 a 1169 mule the sphere 17 15 due in duh EN 15 m the 39 duvcuuu From 1 m 2 Ah m ww dueczmu 1 171 mine the Sphm39t39 II All ms E posxuve n5 Expucted deueased c The maul splm39e becomes polsn39zed so chm n male the sphm Then AV 15 1910 11m AV 2 0mm me 81mm Che E eld ls due 0 the hsks and he polmized sphew AV Sum the negative charge on the thete mm toward me posmvely chmged p then mu potential M 2 and 3 w l be more negmve Since 15 AV M I r V M h 5 town pomts 2 and 3 maxed A e whic men the punenual vanes as me 5quot 2 12mm aha 5mm than V 1 Increased duem me palanzed sphere 111379 3 The dumle moment vectm 15 to the lefn rm Fng 2 A skmh of I h thx0 1 m E is in tho x directon Sim y 2 the 111ng of a proton A139 a A u fox 5 closed system 1 71395 E Lusde the sphere ls ouuwmd mm magmcude Flow 139 g to r39139z AV is r at the suz we R is the same as L point punch v 179100 E s 1 Ma As the same as w umwlmm nmidu LI xplwxm Tm m H hehvwn m m mum mm m when M v m cumum v m rat 1125 1 0 Asmle ulhal v39u3 7 K m use wind 15 KT 1 113106 3 Note that my Etield due u the dlpvb in tins mse Is m m 7y dilution bun the path from A to B is m the it duecm As a xesult Ar f E IT a Emcc E and AT m perpendquLax If you use mperposltmn m get u hen m fyau use spexpulhon than Likewise uamg the swle matheumucs VP a A T1115 agjees with L119 result obtamed by mcegraung A iambi h 1 131354 5 due superposxhcm of BM Him EK m m the 7 duec on and ha a msgmmde A 2 L2110 39T 2 uuflmx EM 5 in the 7 dJleCUDn and has a magmrude gm Hr 39rnu7121 10quot 391 nurwo 111139 Since the given 10mm 15 many mug Lhe am a the lung Etnang pieces then is due to my 1ng straight pxecea 15 H J 39 39 m V l hemxsphere anl f due 0 gt1 hmmsphete of mlm n w a nquot where H b the angle between F and IT mu m 1w 4 shown in Fxgmg Flgum o A sketch shuwmg Important voctozs fut ndmg E 11 Problem 131256 Sluce and I m L m1 sin 90quot 1 ld Ha I 74Fle B The lower hemisphere oreMes a magnetic eld The net mgnehr eld 15 1L5 mgmtude AS Its direcuon 15 B lt 0417 181150 me cum 1 E at L 39 v L A39 a The needle mu be de ected mwud and me lop vlew of the campass wm Appeal hke Fxgule W E Figme a A sketch of the compass in m Jam 18 so Assume n s 5 Lynn con At the cell s centex 181361 a Use the nghphwd rula apphed m esdx stlmght hue segmem 9m side 01le triangle In em use the mguehc eld dun to h side is m the 72 duecun east Thus the Cumpass mu be de ected esslzwaml and mu pom northeast b 3 X the only xeasomble my a mid ch mmng loop a Emdf Lhz lnagne c eld dm Ln one side ofthe criugulax mp Multply by K m Eat E aha mumply by u get Em due m the mil 1 X mg Tm o m m A A 0021111 I J m n24 mu unisz 205 x1lquot j 615 xnrmr E u 3615 A m G T 134 A 10 T The comp de ection hou um th is H HUIl Wquot Bush I 181352 he cml em ows N m the 3 macaw B Eh can 2 x 1 1 5 ILauli 389 x 10b T I N V mu nos m V AX The magnemc uld M 1mm A is LE 5w 417 y 7 L 7 Hr7 Mpmm A U 28 m 410 x W7 T rlxen Now hm Nince I lt L In ho t cam an can more w kly solve Hm praan mth Mina Sinre If x Amwkumm 13 LMHT1 MGAMFTT olvmg m m current 15 not uecessm Since pumt A m 9 me further than the wmpm um BA n 75 he magnetic eld 5 due 0 the wire at he munpass 181374 La mom e 1 H quot b The almco magnet 11 he Mm expenmem kit has n was of appxoxmmtely 13 g or 00m kg Assume the Emmet is 39 m 39 the numbez of mm mm m the umgnel emu m 139 x10 atoms So the megueve cowl mame moment can be emmeced W n e 1 x 1D An11raron11xg x 10quot Mam F 11Am2 T1115 15 Jessomble ageemeul gtven the crude measuxamems 18915 5 ThnN e r e M m T T uwnmm I 18916 n Tluh 139gt s end ls timer m my cumpns The N rrml would 1m Meeml m wmo 1n the otlm mm 1 Al C E pom m wont m mm ix mm A B m D 13 yum mm of um 0 NE 6 w W n 1 5 X104 139 m 1H mJJ ID 1877 a The eldfzom 39 u A 50 B r n r a 1 th bar s s end 15 closer to the compass b Stalmmms 1 and 5 are me c K quot 11 amquot to nd me mll39s q mmm mum Now we a sum fax cm numle of mm x n 35 131219 m A m39uplz proyam 15 Shawn hem mm visuul hupon x Solutmn using H mm sceuevwidlh1024 w x W ace Irnglh a mmmuz m mum rnrhus n snlcnmd m mm mull4m at cunvuntianul cumquot Nnumwn w numb of m m salrnmd 1 Numb5m numb u hm tLyvn M m turn n Jsmllu rum nulr furtm fur B m mmm F runxll39uqt a xulumwl an 4 u curuc a A Ntuxnstclts xx u quotMA2 mm dxx 2 one 7 2p1NcnruaL salmwld curvuxxx y m nmegu Lvausxxnoung may 7m nulms0 ll F mm a m n m In nrmu s a nhscrrnhnn Intuition en meows Ipty 1m n u LJ 1770 tor x in mngep L2gtdx dx 1 u for y in Hm i rlM 70 02 4mm 0 011 012 04 U 05 a muamplluwlpusxyzz nxis0UUl mmm1mcym almftwultl was Barraw appeudnn Chapter 14 4924 A Wm valvnum m m dm mu m hr mH Iaru um um plumIv mmrm mm mm an the munIv u m u Ahmcuan 39 V mm W p r 1 um m39 kg LU M x W gt mgt y 7 lt1u4xm Vgt 7 lt xur gt 4 cm x m r39 7 Lawn I m gt xc V 7 Iu11770sm lum 7 my 7 a n 7 m w WM m r L U M 7mnzxm 7 mm 77 7 7 mnnr VZ m 7 751L3gtltAquotquotL H a7 7 mm x wquot vgm lt 7416711 57741317 gt 7 113xl4l m x w 7m x quotm m my m um 7xdlvrti0u quot and u dxmgcd puma must m w the Inn m m 7 duwruan am uh puml m lhvuunch vhcn A m diml kum nnx mummm Bum mum awuuknmnm m vnumual mm vlnmsr mum Ymmu uflhrar Wm WM Thunl mm Wm m x 4 A dbnmw V 7j illlxl Hump 7 mm Kl M m 7 n x M m m Ilmnc mm Wm mm mm m 4mm munv mmm m MM r m pdmrlr m the kn and r39 7lt 712xmquotu0gt m u m mm k m m A u ng rlwgud mmdu ukmu wmu m mmpn mm Hm Hulmn mml n m m nth I IN puml Mm vuudmh u Hm mm mm th mm palm mmml Llwpamdc m mmM wmg g 7 q MM r A x mquot39 u gt m 141w m 5mm m Ha uurhns mu prawn mug m y quotMS as mm H mm 1 pm m pm x at m ungm rm m 7Axl1r m E E mm m He nucleus prawn mum A Ha mm mm a prawn The nnmu a u m pumt x run aw mm mm m numummmum 11 mm x um Mr 39 N m Wham TluF Jum m m m mm w Km V b y r v 1 nu mmm m mm Tm 7 74m m m Smcv nu pwnm b w m mm of lulungm mm m wnrmu L r7lt 1m x nr uu gt m m Timxlnlmn mus h x um m In mm x luluuw Llw 7 39 n x w AJW u nmmmm mumlmb un gxwulewnu u Swagurr n 39 m pmmmv r7lt 7707 x mquot u u gt m x 2 Smul Tm n 173 E hum electron He nucleus mm 2 A H unrivth Anle mm Thcnnmui r m mm x 4P5 m m m M r39 um mm m 7 n MLU ym I m alwrwtmn hmumn n m 011 krmuun u q Mm b m pwmn 11 m mmmmu lumnuu mm m le pamch lt 7 UUI1 mrg1um i hh 7 474174IJLX1Dm m 7 4w m 71 7 ltux74mugt ax 7mm 39 m 1 MC 337410 41gt 7 71 44 x10 5m x mm m 7 Hm u m 11 limrnr ELMrhuLu Q3 nuhMWHme mhcrvdmwmu Itsumgmlndub 7 a x m7 N39 175x 14v7ugt NC 34 um 11mm wrwr s m Sum lhcohu m mm m m 11 mm mm X Wu N397ltu 7 mm m 39 39 C d QM 7 7 x w r lt7v m m m mim NT wt 7 2m mm m TLuckrlm mmmmm M yumWm mum in llwruduulwn 1L7 magnitude m mm wuur 7 7ltu4 1011 NL E m Tmvhurm nde m a u um U m m Hum 7nuxugtm 11 m mun 7mmquot 7 mm m 71 7 lt 7m 7mm gt m 7 IX 10 lt 7 r 74mugt m x w6 v 7 7 m 39w m Mr X mT V I lt 77 7m 41gt 7 61x mum x mzn xv w m lamM mm a E 7lt l M x winquot my Sum we rlmmnmwmm 1 Q mm 13 u gt N39 ltu Amem x m 773m x 1274 m gtlt mu wv lt 1m x10 7 42m x um I V 1 r E39 7 74 x urquot mu m MAM mquot 4 my 7 7 mumquot 7111411H39r7 v 39mx hu m 4 10quot x mm mu 7 H n x quotm i r 41441Mvum lt 1 4 Eu 7 I mm r M v u Tlnumrrwphould pmm mm the upp nghl 14xss my A 1quot g I39qulrluhdrwlvllwdlpul Mu Lunarthunrtmlh mmmnwm MJLEJ smu I um mmluum mm m mu um um u m um L m Innhum mm dunno m u m w u 12 1270 lt r 211gt1 vgt 7me u u 7ux m n A W Hm lxxml1 AxlU 39m gt7 n m Urwu11gtN77UMU L0 w n4rml w Chapter 15 m I h av Mm mm m m uiLlndlpnh m Llw mmnmmm mmnpm mnmml u MW m unmm n mgmwh mm punch WWW um mm mm A u Imuum mg mum m can qmu g Tth Anmnlnplrvxthumm mmmg m Vm tm awmnd m myx Hmr mm Mum v wt mnm dmnh rim b mm bl lhvdhugul pqru39vlv m rm m hr 1m rtmu unm un m an mu 39139va m vlwmrhdd u mun m gin will mun llwukvnnu mu qulum rv m an pmhm ma llnmtrm m ghmx m m m Lurdmw m mm m thchruun A nusunwnmiuurw m mm mm L thuu v Furn39x m A mm 151143 m m we m m mlnnlwl mm umn un nm 4 mm m A niaguuudv 7 mu Iumltthm llnuul mum mum L nm aflhvruhm Atmnllug u m Hnmcumm Fnuuph 7mm M 7 mm smmm mums m rahuhm 4 mm mquotquotc39 nyc39mu x NWT m n x u mg x11 quotm 7 yxm ow msz m sum 1 x m lhrudnulmuzrlwmumldmmurvmlhlumuv1h mumerkmtmnhxuxArum H3 m 1 Then mm mm Mum Imlhlm llwulwtm mmumu m dipole m A m m dipulvs on ho ch I m 1 mm m Mme m 15X60 my In mm nu ma dmmn mm man the poxlwch39 thung punch mt Mm mm m lwgutnidyrhargwl nnurlc mm a highm39 nmnmmu a negnzlw Wm charge mu n msurwlv rhm gad panHK uul A hwiwr mnwmmuw quotx mm mum Almrge nun me new mug mm Lm s mun a mm 1 E uhl mum a pawn A m E 7 If a um m gm mm H I v V y y t rum Wm wuuwnmxv Luger Inn 12 r 0 so mm m sum a mu m 21 nmdmtnr m mm xmlkr dm m VluLugvr dwmuu Lhml 1 m palmqu a M W hm m sur xrndxalzu mm m vppvmw m E cqumbrmn 151255 m n r rm Thm Lhr mum mm 39 um mm m mum to smu mnll mwm mm mm ler x m mmhllthmk lenu39 lln Am mm uhhugtuu k sulhuf m hsphnx mm Blunthum unnm yum wv 4 r Inc mm Huck m1 usz sph ns m m M r m r w v l ALA m V V V V R unnmquun vr x m n n v v mpnk n unvnrnl m palm E Amp am It I14w215mxlkrdxpulc unnm m 1512 m ngmwu chug Mndmvgnhl muhumhwnmmmm wugwma wpdnulnmuthu m 39 A gnm dvusm ufvlcrtmui L n hr um um Khv g a m A may dmsih of v mm nu LN mm mwi m rth x mm n lvfw duugt many m x 1 ummmuou n ugh sup uwm mm m sphtn39 m BMW MWN HKHMME mummu MM m MW Ahrwuun Tlmrcimc I us han cuun w x39 uugt 7 lt 3200 a 41gt cv 151111 a 11m unlfm39mlv plasma emu mm 1 mmch M puml mmch ns cnm m 7 mmvtmn m umguuudv 11 mm 314 mm mm a 13 mm m m a re rlw Budd as a Mum A I 4 V quotiwAuw m mmnv unculcddlpuk mu Llnxdlpuk39 n has nan mnmcm y 7w m m 7 umch Paint an Llw 39 v n v r v 4 L V n 7 w mu m mm u u Mlur 151271 m m m umrmm Mm yell mu 7 dimmu n magnum x Madam point Wm mum JinnnlcxmAuktmc mum 13mm m mu m mm u u Mlur me r5 5 an m um mm m 11mm as a mum Things you must know Relationship between electric eld and electric force Conservation of charge Electric eld of a point charge The Superposition Principle Relationship between magnetic eld and magnetic force Magnetic eld of a moving point charge Other Fundamental Concepts d dl id d Fnet and pzmd ifvltltc AUelq V AV 2E1AmEyAyEzAz ltIgtelfE dA QmagfB dA fE dAM fE dA0 60 n a 1391 lemfl fENC dl f3 I dl MOZIinsidepath a s d a A fB39dlM0Zhnsidepath l oafE39ndA Speci c Results a 1 2 s c d 5 Edipoleyams m 4 eor qg on ans 7 gtgt 8 Edipolei m 47T 0 3 on 1 ax1s 7 gtgt 8 s 1 a Emd 7 1 from center electric dipole moment p 15 77 or Eapplied N 1 2QL d 7 1 IZ Emd N 47T OT if 7 lt L Ermg 7 m z2 R232 z along ax1s 7 214 Z 1 N A z N QA lEdwk 2 60 1 Z mg a N 260 ll El 260 lt1 lt R Q A 1 Q A s i i Ecapacitor and Q dlsks Efrmge 60 Just outside capacitor 4 AZ A a a s AB EA short Wire AF Al X B 47139 7 2 7 7 M0 L N 0 21 7 7 wae 7 7 lt L szre 7 Bearth tanO a 7 M0 2177132 N 1L0 2177132 7 7 2 Bleep iEWNE Z3 on ax1szgtgtR 71147le a 2 7 Bdipole mis on mm 7 gtgt 8 Bdipol m on 1 ax1s 7 gtgt 5 a 1 7 A A A n Erad E Nld 4 12 i v E Hld X Brad Brad 713960 c 7 c inAv IlqlnAv vuE I L E a lql nu J A a 0A E 7 1 1 Edielectric M AV q due to a point charge K 47T 0 7 f 7 i


Buy Material

Are you sure you want to buy this material for

25 Karma

Buy Material

BOOM! Enjoy Your Free Notes!

We've added these Notes to your profile, click here to view them now.


You're already Subscribed!

Looks like you've already subscribed to StudySoup, you won't need to purchase another subscription to get this material. To access this material simply click 'View Full Document'

Why people love StudySoup

Jim McGreen Ohio University

"Knowing I can count on the Elite Notetaker in my class allows me to focus on what the professor is saying instead of just scribbling notes the whole time and falling behind."

Anthony Lee UC Santa Barbara

"I bought an awesome study guide, which helped me get an A in my Math 34B class this quarter!"

Steve Martinelli UC Los Angeles

"There's no way I would have passed my Organic Chemistry class this semester without the notes and study guides I got from StudySoup."


"Their 'Elite Notetakers' are making over $1,200/month in sales by creating high quality content that helps their classmates in a time of need."

Become an Elite Notetaker and start selling your notes online!

Refund Policy


All subscriptions to StudySoup are paid in full at the time of subscribing. To change your credit card information or to cancel your subscription, go to "Edit Settings". All credit card information will be available there. If you should decide to cancel your subscription, it will continue to be valid until the next payment period, as all payments for the current period were made in advance. For special circumstances, please email


StudySoup has more than 1 million course-specific study resources to help students study smarter. If you’re having trouble finding what you’re looking for, our customer support team can help you find what you need! Feel free to contact them here:

Recurring Subscriptions: If you have canceled your recurring subscription on the day of renewal and have not downloaded any documents, you may request a refund by submitting an email to

Satisfaction Guarantee: If you’re not satisfied with your subscription, you can contact us for further help. Contact must be made within 3 business days of your subscription purchase and your refund request will be subject for review.

Please Note: Refunds can never be provided more than 30 days after the initial purchase date regardless of your activity on the site.