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# MGt 218 : Chapter 9 : Hypothesis tests about the Mean and proportion MGT 218

Marketplace > Marshall University > Business > MGT 218 > MGt 218 Chapter 9 Hypothesis tests about the Mean and proportion
Winn
Marshall
GPA 3.72

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First part of the next exam.
COURSE
Introductory Statistics
PROF.
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Class Notes
PAGES
5
WORDS
CONCEPTS
Statistics.
KARMA
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This 5 page Class Notes was uploaded by Winn on Thursday March 31, 2016. The Class Notes belongs to MGT 218 at Marshall University taught by in Spring 2016. Since its upload, it has received 10 views. For similar materials see Introductory Statistics in Business at Marshall University.

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Date Created: 03/31/16
Chapter 9 : Hypothesis T ests about the Mean and Proportion. Book : Introductory Statistics – Prem S.Mann Explaining Important More Important This lesson explains how to conduct a hypothesis test of a mean, when the following conditions are met:  The sampling method is simple random sampling.  The sampling distribution is normal or nearly normal. Generally, the sampling distribution will be approximately normally distributed if any of the following conditions apply.  The population distribution is normal.  The population distribution is symmetric, unimodal, without outliers, and the sample size is 15 or less.  The population distribution is moderately skewed, unimodal, without outliers, and the sample size is between 16 and 40.  The sample size is greater than 40, without outliers. This approach consists of four steps: (1) state the hypotheses, (2) formulate an analysis plan, (3) analyze sample data, and (4) interpret results. State the Hypotheses Every hypothesis test requires the analyst to state a null hypothesis and an alternative hypothesis. The hypotheses are stated in such a way that they are mutually exclusive. That is, if one is true, the other must be false; and vice versa. The table below shows three sets of hypotheses. Each makes a statement about how the population mean μ is related to a specified value M. (In the table, the symbol ≠ means " not equal to ".) Null Alternative Number of Set hypothesis hypothesis tails 1 μ = M μ ≠ M 2 2 μ > M μ < M 1 3 μ < M μ > M 1 The first set of hypotheses (Set 1) is an example of a two-tailed test, since an extreme value on either side of the sampling distribution would cause a researcher to reject the null hypothesis. The other two sets of hypotheses (Sets 2 and 3) are one-tailed tests, since an extreme value on only one side of the sampling distribution would cause a researcher to reject the null hypothesis Hypothesis Testing For a Population Mean The Idea of Hypothesis Testing Suppose we want to show that only children have an average higher cholesterol level than the national average. It is known that the mean cholesterol level for all Americans is 190. Construct the relevant hypothesis test: H : m = 190 0 H 1 m > 190 We test 100 only children and find that x = 198 and suppose we know the population standard deviation s = 15. Do we have evidence to suggest that only children have an average higher cholesterol level than the national average? We have z is called the test statistic. Since z is so high, the probability that Ho is true is so small that we decide to reject H0and accept H . 1herefore, we can conclude that only children have a higher average cholesterol level than the national average. Rejection Regions Suppose that a = .05. We can draw the appropriate picture and find the z score for -.025 and .025. We call the outside regions the rejection regions. We call the blue areas the rejection region since if the value of z falls in these regions, we can say that the null hypothesis is very unlikely so we can reject the null hypothesis Example 50 smokers were questioned about the number of hours they sleep each day. We want to test the hypothesis that the smokers need less sleep than the general public which needs an average of 7.7 hours of sleep. We follow the steps below. A. Compute a rejection region for a significance level of .05. B. If the sample mean is 7.5 and the population standard deviation is 0.5, what can you conclude? Solution First, we write write down the null and alternative hypotheses H 0 m = 7.7 H 1 m < 7.7 This is a left tailed test. The z-score that corresponds to .05 is -1.645. The critical region is the area that lies to the left of -1.645. If the z- value is less than -1.645 there we will reject the null hypothesis and accept the alternative hypothesis. If it is greater than -1.645, we will fail to reject the null hypothesis and say that the test was not statistically significant. We have Since -2.83 is to the left of -1.645, it is in the critical region. Hence we reject the null hypothesis and accept the alternative hypothesis. We can conclude that smokers need less sleep.

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