Why is base (NaOH or KOH) added as a second step in each of the reactions shown in Eqs
Chapter 23, Problem 23.15(choose chapter or problem)
Why is base (NaOH or KOH) added as a second step in each of the reactions shown in Eqs. 23.23 and 23.24? (Hint: What is the form of the product after the reduction step? Refer to Sec. 23.5A.)
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