(II) Figure 4-53 shows a block (mass mA) on a smooth horizontal surface, connected by a thin cord that passes over a pulley to a second block which hangs vertically, (a) Draw a free-body diagram for each block, (mB), showing the force of gravity on each, the force (tension) exerted by the cord, and any normal force. (h) Apply Newton's second law to find formulas for the acceleration of the system and for the tension in the cord. Ignore friction and the masses of the pulley and cord.
Solution 31P: We have to draw the free body diagram of each body which is moving under the action of gravity and with the help of these free body diagram we have to find out the acceleration of the block and tension in the supporting string. Step 1 of 3 Concept: Newton’s second law: The net force F acting on an object of mass m produces an acceleration a in that object. Mathematically, F= ma. Free body diagram of a body gives the diagrammatical representation of all the forces acting on the body in terms of magnitude and diagram, under the given situation. Step 2 of 3 A] Free body diagram of each block is shown in figures below F Tension in the cord T a Acceleration of the system F N1 Normal reaction on the first block mAg Weight of the first block mBg Weight of the second block As all the surface are frictionless and masses of the pulley and the cord are ignored. When the system is released from rest, the acceleration of the boxes will as shown in the figure above. Considering motion towards the right direction and the downward motion to be positive.