A 0.005 00-kg bullet traveling horizontally with speed1.00 3 103 m/s strikes an 18.0-kg
Chapter 11, Problem 41(choose chapter or problem)
A 0.005 00-kg bullet traveling horizontally with speed1.00 3 103 m/s strikes an 18.0-kg door, embedding itself10.0 cm from the side opposite the hinges as shown inFigure P11.41. The 1.00-m wide door is free to swingon its frictionless hinges. (a) Before it hits the door,does the bullet have angular momentum relative to thedoors axis of rotation? (b) If so, evaluate this angularmomentum. If not, explain why there is no angularmomentum. (c) Is the mechanical energy of the bulletdoor system constant during this collision? Answerwithout doing a calculation. (d) At what angular speeddoes the door swing open immediately after the collision?(e) Calculate the total energy of the bulletdoorsystem and determine whether it is less than or equalto the kinetic energy of the bullet before the collision.
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