Archery 1: An archer climbs a tree near the edge of a cliff, then shoots an arrow high into the air. The arrow goes up, then comes back down, going over the cliff and landing in the valley, 30 m below the top of the cliff. The arrows height, y, in meters above the top of the cliff depends on the time, x, in seconds, since the archer released it. Figure 1-1g shows the height as a function of time. a. What was the approximate height of the arrow at 1 second? At 5 seconds? How do you explain the fact that the height is negative at 5 seconds? b. At what two times was the arrow at 10 m above the ground? At what time does the arrow land in the valley below the cliff? c. How high was the archer above the ground at the top of the cliff when she released the arrow? d. Why can you say that altitude is a function of time? Why is time not a function of altitude? e. What is the domain of the function? What is the corresponding range?
Step by step solution
Step 1 of 1
Consider the graph
a)The approximate height of the arrow at 1 second is 20 m.
At 5 sec -17.5 m ,it is below the top of the cliff that's why.