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Find the two possible values of c3 and the two possible values of the third direction

Precalculus with Trigonometry: Concepts and Applications | 1st Edition | ISBN: 9781559533911 | Authors: Foerster ISBN: 9781559533911 468

Solution for problem R.7 Chapter 10-9

Precalculus with Trigonometry: Concepts and Applications | 1st Edition

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Precalculus with Trigonometry: Concepts and Applications | 1st Edition | ISBN: 9781559533911 | Authors: Foerster

Precalculus with Trigonometry: Concepts and Applications | 1st Edition

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Problem R.7

Find the two possible values of c3 and the two possible values of the third direction angle, . d. Show algebraically, using the Pythagorean property, that there is no vector with direction angles = 30 and = 40. Explain geometrically why such a vector cannot exist. R

Step-by-Step Solution:
Step 1 of 3

a c,Fttnqv weer 5 Notes Monaay 1/rb /t-t \Nearc Acids (HA) and hud fonization Lonstnnil H5po+r-,etica\; HA.- HzO :' H.C' v{ea\lctcrcA Dese aad "ba.seJt*r, o @ s+1ongzrt4 ' we FnoW eqil[priurn,f{eeis a\wa-Ss Which tertsus A- is sry.onq€r basc in*h€rxf\-/ ,bo{seratiq:,HA,ac-iclb ase glgqp-of Strong"er , , nO\A, A- is ,'yaq1LVAse 'becAvr"5f, Ofl-fs atu)ags theS-Wungest base,@ e4. For +he reqc+ion: HA * H'O=ttr$*rA-, (a-- tH'o.Jq * (s1is +freo,c(d 1 [+lA]"q.q i0niz0+1Dnconstant '/,foniza*ronoT +1A = /Lu*linit.ar3 *Lffi f-Lu'o-]oq

Step 2 of 3

Chapter 10-9, Problem R.7 is Solved
Step 3 of 3

Textbook: Precalculus with Trigonometry: Concepts and Applications
Edition: 1
Author: Foerster
ISBN: 9781559533911

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Find the two possible values of c3 and the two possible values of the third direction