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Oscillating Mass: Period Calculation for 0.2 m Displacement
Chapter 5, Problem 5.9(choose chapter or problem)
The maximum displacement of a mass oscillating about its equilibrium position is 0.2 m, and its maximum speed is 1.2 m/s. What is the period \(\tau\) of its oscillations?
Questions & Answers
QUESTION:
The maximum displacement of a mass oscillating about its equilibrium position is 0.2 m, and its maximum speed is 1.2 m/s. What is the period \(\tau\) of its oscillations?
ANSWER:Step 1 of 3
The period of the oscillations of the mass is given by,
\(\tau=\frac{2 \pi}{\omega} \dots \dots(1)\)
Here, \(\omega\) is the angular frequency.
The maximum speed of the oscillating mass is given by,
\(v_{0}=\omega x_{0}\)
Here, \(x_{0}\) is the maximum displacement of the oscillating mass from its equilibrium position.
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Oscillating Mass: Period Calculation for 0.2 m Displacement
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Join us to unravel the mystery of oscillations! In this video, we'll determine the period of a mass oscillating with a 0.2 m displacement and 1.2 m/s maximum speed. Explore the physics behind periodic motion and discover the key to calculating its period. Dive into the world of harmonic motion with us!