Solution Found!
A 1.0-mL volume of seawater contains about 4.0 × 1012 g of
Chapter 1, Problem 83P(choose chapter or problem)
A 1.0-mL volume of seawater contains about \(4.0\times10^{-12}\mathrm{\ g}\) of gold. The total volume of ocean water is \(1.5\times10^{21}\mathrm{\ L}\). Calculate the total amount of gold (in grams) that is present in seawater, and the worth of the gold in dollars (see Problem 1.82). With so much gold out there, why hasn't someone become rich by mining gold from the ocean?
Questions & Answers
QUESTION:
A 1.0-mL volume of seawater contains about \(4.0\times10^{-12}\mathrm{\ g}\) of gold. The total volume of ocean water is \(1.5\times10^{21}\mathrm{\ L}\). Calculate the total amount of gold (in grams) that is present in seawater, and the worth of the gold in dollars (see Problem 1.82). With so much gold out there, why hasn't someone become rich by mining gold from the ocean?
ANSWER:
Step 1 of 4
Here we have to calculate the total amount of gold (in grams) that is present in seawater, and the worth of the gold in dollars.