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(a) Using the ion-pair equilibrium constant from Appendix J, with activity coefficients

Quantitative Chemical Analysis | 8th Edition | ISBN: 9781429218153 | Authors: Daniel C. Harris ISBN: 9781429218153 475

Solution for problem 12-E Chapter 12

Quantitative Chemical Analysis | 8th Edition

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Quantitative Chemical Analysis | 8th Edition | ISBN: 9781429218153 | Authors: Daniel C. Harris

Quantitative Chemical Analysis | 8th Edition

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Problem 12-E

(a) Using the ion-pair equilibrium constant from Appendix J, with activity coefficients 1, find the concentrations of species in 0.025 M MgSO4. Hydrolysis of the cation and anion near neutral pH is negligible. Only consider ion-pair formation. You can solve this problem exactly with a quadratic equation. Alternatively, if you use Solver, set Precision to 1e-6 (not 1e-16) in the Solver Options. If Precision is much smaller, Solver does not find a satisfactory solution. The success of Solver in this problem depends on how close your initial guess is to the correct answer. (b) Compute a new ionic strength and repeat part (a) with new activity coefficients from the Davies equation. Perform several iterations until the ionic strength is constant. The fraction of ion pairing that you find should be close to that in Box 7-1, which was derived with Debye-Hckel activity coefficients. (c) We naively assigned the ionic strength of 0.025 M MgSO4 to be 0.10 M. What is the actual ionic strength of this solution? 1

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Chapter Four Relevant Periodic Groups 1) Group 1A = Alkali Metals *they have a charge of ​1+ 2) Group 2A = Alkaline Earth Metals *they have a charge of ​2+ 3) Group 7A = Halogens * they have a charge of ​1­ 4) Group 8A= Noble Gases * they are neutral. They don’t bond with anything. Elements are formed by nuclear reactions in stars at high temperatures. Rules for Orbital Filling 1) Pauli Exclusion Principle → No two electrons have same four quantum number. 2) Hund’s Rule → Electrons will pair only if there is no orbital of exactly the same energy available 3) Aufbau Principle → Electrons fill in this order ; 1s,2s,2p,3s,3p….etc EXCEPTIONS 1s,2s,3s,3p,4s,​3d​,

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Chapter 12, Problem 12-E is Solved
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Textbook: Quantitative Chemical Analysis
Edition: 8
Author: Daniel C. Harris
ISBN: 9781429218153

This full solution covers the following key subjects: . This expansive textbook survival guide covers 55 chapters, and 1224 solutions. The full step-by-step solution to problem: 12-E from chapter: 12 was answered by , our top Chemistry solution expert on 03/16/18, 04:33PM. This textbook survival guide was created for the textbook: Quantitative Chemical Analysis, edition: 8. The answer to “(a) Using the ion-pair equilibrium constant from Appendix J, with activity coefficients 1, find the concentrations of species in 0.025 M MgSO4. Hydrolysis of the cation and anion near neutral pH is negligible. Only consider ion-pair formation. You can solve this problem exactly with a quadratic equation. Alternatively, if you use Solver, set Precision to 1e-6 (not 1e-16) in the Solver Options. If Precision is much smaller, Solver does not find a satisfactory solution. The success of Solver in this problem depends on how close your initial guess is to the correct answer. (b) Compute a new ionic strength and repeat part (a) with new activity coefficients from the Davies equation. Perform several iterations until the ionic strength is constant. The fraction of ion pairing that you find should be close to that in Box 7-1, which was derived with Debye-Hckel activity coefficients. (c) We naively assigned the ionic strength of 0.025 M MgSO4 to be 0.10 M. What is the actual ionic strength of this solution? 1” is broken down into a number of easy to follow steps, and 168 words. Quantitative Chemical Analysis was written by and is associated to the ISBN: 9781429218153. Since the solution to 12-E from 12 chapter was answered, more than 244 students have viewed the full step-by-step answer.

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(a) Using the ion-pair equilibrium constant from Appendix J, with activity coefficients