Solution Found!

Solved: An aluminum cylinder is 10.0 cm in length and has

Chapter 1, Problem 91P

(choose chapter or problem)

Get Unlimited Answers
QUESTION:

An aluminum cylinder is 10.0 cm in length and has a radius of 0.25 cm. If the mass of a single Al atom is \(4.48\times10^{-23}\mathrm{\ g}\), calculate the number of Al atoms present in the cylinder. The density of aluminum is \(2.70\mathrm{\ g}/\mathrm{cm}^3\)

Questions & Answers

QUESTION:

An aluminum cylinder is 10.0 cm in length and has a radius of 0.25 cm. If the mass of a single Al atom is \(4.48\times10^{-23}\mathrm{\ g}\), calculate the number of Al atoms present in the cylinder. The density of aluminum is \(2.70\mathrm{\ g}/\mathrm{cm}^3\)

ANSWER:

Step 1 of 3

Given:

Length of aluminum cylinder = 10.0 cm.

Radius of aluminum cylinder = 0.25 cm.

Mass of a single Al atom =  g.

Density of aluminum = .

The Number of Al atoms present in the cylinder =?

 

Add to cart


Study Tools You Might Need

Not The Solution You Need? Search for Your Answer Here:

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back