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The partition coefficient for a solute in chromatography is K cs/cm, where cs is the

Quantitative Chemical Analysis | 8th Edition | ISBN: 9781429218153 | Authors: Daniel C. Harris ISBN: 9781429218153 475

Solution for problem 22-17 Chapter 22

Quantitative Chemical Analysis | 8th Edition

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Quantitative Chemical Analysis | 8th Edition | ISBN: 9781429218153 | Authors: Daniel C. Harris

Quantitative Chemical Analysis | 8th Edition

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Problem 22-17

The partition coefficient for a solute in chromatography is K cs/cm, where cs is the concentration in the stationary phase and cm is the concentration in the mobile phase. The larger the partition coefficient, the longer it takes a solute to be eluted. Explain why.

Step-by-Step Solution:
Step 1 of 3

The bigger Ka is, the stronger the acid is, and the less basic that its anion is. For all strong acids, the anion is neutral, but for weak acids, the anion is basic. Ex. Perchlorate and sulfate are neutral anions, but fluoride and cyanide are basic anions. If a salt contains a basic anion, the salt will form a basic solution when dissolved in water. Ex. Sodium acetate, potassium fluoride. Useful equations for pH problems: −¿ OH ¿ ¿ ¿ +¿ H ¿ ¿ ¿ pKa+pKb=14 Sample problem: You have a solution of 0.1 M HCl and 0.1 M HF. Calculate the pH. The HCl will dissociate completely, so that the concentration of the free hydrogen ions will be equal to the HCl concentration. The HF does not dissociate completely. It dissociates according to the following equation:

Step 2 of 3

Chapter 22, Problem 22-17 is Solved
Step 3 of 3

Textbook: Quantitative Chemical Analysis
Edition: 8
Author: Daniel C. Harris
ISBN: 9781429218153

Quantitative Chemical Analysis was written by and is associated to the ISBN: 9781429218153. The answer to “The partition coefficient for a solute in chromatography is K cs/cm, where cs is the concentration in the stationary phase and cm is the concentration in the mobile phase. The larger the partition coefficient, the longer it takes a solute to be eluted. Explain why.” is broken down into a number of easy to follow steps, and 45 words. This full solution covers the following key subjects: . This expansive textbook survival guide covers 55 chapters, and 1224 solutions. The full step-by-step solution to problem: 22-17 from chapter: 22 was answered by , our top Chemistry solution expert on 03/16/18, 04:33PM. Since the solution to 22-17 from 22 chapter was answered, more than 228 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Quantitative Chemical Analysis, edition: 8.

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