A 50.0-mL sample of 0.080 0 M KSCN is titrated with 0.040 0 M Cu. The solubility product
Chapter 26, Problem 26-E(choose chapter or problem)
A 50.0-mL sample of 0.080 0 M KSCN is titrated with 0.040 0 M Cu. The solubility product of CuSCN is 4.8 1015. At each of the following volumes of titrant, calculate pCu, and construct a graph of pCu versus milliliters of Cu added: 0.10, 10.0, 25.0, 50.0, 75.0, 95.0, 99.0, 99.9,100.0, 100.1, 101.0, 110.0 mL. 26-F
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