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Get Full Access to Statics And Mechanics Of Materials - 5 Edition - Chapter 5.4 - Problem 5-28
Get Full Access to Statics And Mechanics Of Materials - 5 Edition - Chapter 5.4 - Problem 5-28

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# Dctem1ine the force in members BC, BE, and EF of the truss and state if these members

ISBN: 9780134382593 479

## Solution for problem 5-28 Chapter 5.4

Statics and Mechanics of Materials | 5th Edition

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Statics and Mechanics of Materials | 5th Edition

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Problem 5-28

Dctem1ine the force in members BC, BE, and EF of the truss and state if these members are in tension or compression. Set P1=6 kN, P2 = 9 kN, and P3 = 12 kN.

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ENGR 103 Lecture 19 Resistance- the ability of an object to restrict or resist the flow of electrons in an electrical circuit - measured in ohms (Ω) Resistor- the circuit element responsible for restricting the flow of electrons - absorb energy from the electrons and dissipate it as heat - since there is a transfer of energy through a resistor, this means a difference in energy levels occur across the resistor constituting a voltage Ohms’s Law - Math: V = IR= 1 volt is equal to 1 ohm multiplied by the current (I) o Also one ohm= 1 volt divided by 1 Amp (I) - Passive sign convention must always be applied ; there for resistance is always positive - Circuit elements can be connected together in either a series or parallel way Series: elements in a series form a connection from end to end (like a train) - N number of Resistors in series can be combined to create a single equivalent resistance o Req Series= R1+R2+R3+…+RN - The current through each resistor is the Same o Iseries= I1=I2=I3=..,=IN - The total voltage drop across the equivalent resistance is equal to the sum of all individual resistor voltage drops o V series= V1+V2+V3…+VN Parallel Resistance= elements connect across each other like rungs of a ladder. - N number of resistors in parallel can be combined to create a single equivalent resistance o 1/ Req par. = 1/R1+1/R

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