If two gases have molar masses M1 and M2, Grahams law states that the ratio R of their
Chapter 3, Problem 10(choose chapter or problem)
If two gases have molar masses \(M_{1} \text { and } M_{2}\), Graham’s law states that the ratio R of their rates of effusion through a small opening is given by \(R=\sqrt{M_{1} / M_{2}}\) The effusion rate of an unknown gas through a small opening is measured to be \(1.66 \pm 0.03\) times greater than the effusion rate of carbon dioxide. The molar mass of carbon dioxide may be taken to be \(44 \mathrm{~g} / \mathrm{mol}\) with negligible uncertainty.
a. Estimate the molar mass of the unknown gas, and find the uncertainty in the estimate.
b. Find the relative uncertainty in the estimated molar mass.
Equation Transcription:
Text Transcription:
M1 and M2
R=\sqrt M1/M2
1.66 \pm 0.03
44 g/mol
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer