Get answer: The following MINITAB output presents the results of a hypothesis test for a

Chapter 6, Problem 14

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The following MINITAB output presents the results of a hypothesis test for a population mean $\mu$.

One-Sample Z: X

Test of mu = 73.5 vs not = 73.5

The assumed standard deviation = 2.3634

Variable N Mean StDev SE Mean 95% CI Z P

X 145 73.2461 2.3634 0.1963 (72.8614, 73.6308) −1.29 0.196

a. Is this a one-tailed or two-tailed test?

b. What is the null hypothesis?

c. What is the P-value?

d. Use the output and an appropriate table to compute the P-value for the test of

$H_{0}: \mu \geq 73.6 \text { versus } H_{1}: \mu<73.6$

e. Use the output and an appropriate table to compute a 99% confidence interval for $\mu$

Equation Transcription:

$\mu{}$

${H}_{0}:\mu{}\geq{}73.6\ versus\ {H}_{1}:\mu{}<73.6$

$\mu{}$

Text Transcription:

\mu

H_{0}: \mu \geq 73.6 \text { versus } H_{1}: \mu<73.6

\mu

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