A copper smelting process is supposed to reduce the arsenic content of the copper to

Chapter 6, Problem 6

(choose chapter or problem)

A copper smelting process is supposed to reduce the arsenic content of the copper to less than 1000 ppm. Let \(\mu\) denote the mean arsenic content for copper treated by this process, and assume that the standard deviation of arsenic content is \(\sigma=100 \mathrm {\ ppm}\). The sample mean arsenic content \(\bar{X}\) of 75 copper specimens will be computed, and the null hypothesis \({H}_{0}: \mu \geq 1000\) will be tested against the alternate \(H_{1}: \mu<1000\).

a. A decision is made to reject \(H_0\) if \(\bar{X} \leq 980\). Find the level of this test.

b. Find the power of the test in part (a) if the true mean content is 965 ppm.

c. For what values of \(\bar{X}\) should \(H_0\) be rejected so that the power of the test will be 0.95 when the true mean content is 965?

d. For what values of \(\bar{X}\) should \(H_0\) be rejected so that the level of the test will be 5%?

e. What is the power of a 5% level test if the true mean content is 965 ppm?

f. How large a sample is needed so that a 5% level test has power 0.95 when the true mean content is 965 ppm?

Equation Transcription:

Text Transcription:

mu

sigma=100 ppm

bar{X}

H_0:1000

H_1:<1000

H_0

bar{X}{</=}980

bar{X}

H_0

bar{X}

H_0

Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.

Becoming a subscriber
Or look for another answer

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back