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Converting a Fischer projection to a perspective formula. Determine the configuration

Organic Chemistry | 8th Edition | ISBN: 9780134042282 | Authors: Paula Yurkanis Bruice ISBN: 9780134042282 482

Solution for problem 6 Chapter 4

Organic Chemistry | 8th Edition

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Organic Chemistry | 8th Edition | ISBN: 9780134042282 | Authors: Paula Yurkanis Bruice

Organic Chemistry | 8th Edition

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Problem 6

Converting a Fischer projection to a perspective formula. Determine the configuration ofeach of the two asymmetric centers in the Fischer projection. Draw the three solid lines of theperspective formula. Add a solid and hatched wedge at each carbon (making sure the solidwedge is below the hatched wedge) and then add the lowest-priority group on each carbon tothe hatched wedge. Now add the other two groups to each carbon in a way that will give thedesired configuration at each asymmetric carbon.

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CHEM 51 WEEK 1 INTRO TO ORGO The beginning of organic chemistry began with the formation of earth’s primordial atmosphere, when CO, NH3, CO2, HCN collided under a lot of pressure, heat, and energy, forming purines and pyrimidines, the basis of life, and amino acids, which formed peptides, proteins, and enzymes. 1828: Fredrich Wohler proved that the theory behind “vital force” was incorrect and that one could synthesize organic compounds from inorganic compounds: This lead to a structural theory—how atoms are put together to form molecules. Ionic bond: transfer of e- Covalent bond: sharing of e- Simplistic model of an atom: *mostly space *each shell contains a maximum number of e-: 2, 8, 18 *maximum stability associated with filled shells or those that contain 8 e- *electronegative elements gain e- to fill outer shell *electropositive elements donate e- to obtain filled outer shell Every bond is an exothermic reaction. We lose energy in bonds because energy + attraction are being concentrated and becoming denser, thus entropy decreases The possibilities for carbon are basically endless. Located in group 4, it has the ability to bond to almost anything and create any kind of structure. Atomic orbitals: how molecules get their shape S-orbitals: spherical p-orbitals: dumbbell shaped d-orbitals: Electron configuration rules: 1) A

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Chapter 4, Problem 6 is Solved
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Textbook: Organic Chemistry
Edition: 8
Author: Paula Yurkanis Bruice
ISBN: 9780134042282

This full solution covers the following key subjects: . This expansive textbook survival guide covers 127 chapters, and 2116 solutions. This textbook survival guide was created for the textbook: Organic Chemistry, edition: 8. Since the solution to 6 from 4 chapter was answered, more than 239 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 6 from chapter: 4 was answered by , our top Chemistry solution expert on 03/16/18, 04:59PM. The answer to “Converting a Fischer projection to a perspective formula. Determine the configuration ofeach of the two asymmetric centers in the Fischer projection. Draw the three solid lines of theperspective formula. Add a solid and hatched wedge at each carbon (making sure the solidwedge is below the hatched wedge) and then add the lowest-priority group on each carbon tothe hatched wedge. Now add the other two groups to each carbon in a way that will give thedesired configuration at each asymmetric carbon.” is broken down into a number of easy to follow steps, and 80 words. Organic Chemistry was written by and is associated to the ISBN: 9780134042282.

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Converting a Fischer projection to a perspective formula. Determine the configuration