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The second-order rate constant (in units of M- 1s - 1) for acid-catalyzed hydration at

Organic Chemistry | 8th Edition | ISBN: 9780134042282 | Authors: Paula Yurkanis Bruice ISBN: 9780134042282 482

Solution for problem 72 Chapter 6.16

Organic Chemistry | 8th Edition

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Organic Chemistry | 8th Edition | ISBN: 9780134042282 | Authors: Paula Yurkanis Bruice

Organic Chemistry | 8th Edition

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Problem 72

The second-order rate constant (in units of M- 1s - 1) for acid-catalyzed hydration at 25 C is given for each of the following alkenes:a. Calculate the relative rates of hydration of the alkenes. (Hint: Divide each rate constant by the smallest rate constant of the series: 3.51 * 10 - 8.)b. Why does (Z)-2-butene react faster than (E)-2-butene?c. Why does 2-methyl-2-butene react faster than (Z)-2-butene?d. Why does 2,3-dimethyl-2-butene react faster than 2-methyl-2-butene?

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Chapter 1 ­ Sig Figs: RULES TO FOLLOW: 1. Leading zeros NEVER count (Ex. of a leading zero is 012). 2. Trailing zeros only count if there is a decimal point written (Ex. of a trailing zero w/o decimal is 120) (Ex. of a trailing zero with decimal is 1200.). 3. All numbers that aren’t leading or trailing zeros ALWAYS count. ­ How to determine how many sig figs there are WITH A DECIMAL: DOT RIGHT! Start with the first real number! Ex: 1.35700 = 6 sig figs. Ex: 0.00750 = 3 sig figs. Ex: 2.500 x 10^­3 = 4 sig figs. Ex: 3.85020 x 10^­22 = 6 sig figs. Ex: 1200. = 4 sig figs. Ex: 70010. = 5 sig figs. Ex: 100. and .100 = 3 sig figs. ­ How to determine how many sig figs there are WITHOUT A DECIMAL: DOT LEFT! Start with the first real number! Ex: 100 = 1 sig fig. Ex: 120 = 2 sig figs. Ex: 37,000 = 2 sig figs. Ex: 012 = 2 sig figs. LEADING ZEROS NEVER COUNT! Ex: 7001 = 4 sig figs. Ex: 70010 = 4 sig figs. THE LAST ZERO DOES NOT COUNT! ­ Multiplication(x)/Division(/) = The answer has the same number of sig figs as the original number with the fewest sig figs. Example 1:​ Let’s say you drove a car 573.4 miles in 7.5 hours, and you wanted to calculate how many miles per hour you traveled. (4 SF) ​73.4 miles= 76.4533333 miles/hour = 7​6 miles/hour. (2 SF) 7.5 hours Example 2: 30 miles per gallon (1 SF). (4 SF) How many gallons of gas do I need to travel 3895 miles 3895 miles x 1 gallo = 129.833 gallons​= 1 x 10^2 gallons. 3

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Chapter 6.16, Problem 72 is Solved
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Textbook: Organic Chemistry
Edition: 8
Author: Paula Yurkanis Bruice
ISBN: 9780134042282

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The second-order rate constant (in units of M- 1s - 1) for acid-catalyzed hydration at