Write equations for the reaction of each compound with H2SO4, a strong protic acid

Molecular Nitrogen The contributions to the MO from each of the atoms is unequal – ψ = cAφ(A) + c B(B) +.......The more electronegative atom contributes strongly to the bonding orbital The less electronegative atom contributes strongly to the anti-bonding orbital – gives rise to polarity Orbital mixing The difference in energy between orbitals on different atoms leads to reduced mixing – The reduced mixing does not imply weaker bonding Heteronuclear Molecules The relative energy of the bonding orbitals determines the magnitude of the covalent bond energy (ΔE cov) Hydrogen Fluoride In H-F the 1s orbital of H is energetically well above the 1s and 2s orbitals of F – it interacts only with the 2z orbital (all remaining electrons are in non- bonding orbitals!) Lithium Fluoride As the polarity difference between two atoms increases, the orbital energy difference also increases – electrons shift towards the more electronegative atom Limiting case: Ionic compounds