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# Two equal masses m move on a frictionless horizontal

ISBN: 9781891389221 90

## Solution for problem 11.24 Chapter 11

Classical Mechanics | 0th Edition

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Classical Mechanics | 0th Edition

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Problem 11.24

Two equal masses m move on a frictionless horizontal table. They are held by three identical taut strings (each of length L, tension T), as shown in Figure 11.19, so that their equilibrium position is a straight line between the anchors at A and B. The two masses move in the transverse (y) direction, but not in the longitudinal (x) direction. Write down the Lagrangian for small displacements, and find and describe the motion in the corresponding normal modes. [Hint: "Small" displacements have yi and y2 much less than L, which means that you can treat the tensions as constant. Therefore the PE of each string is just Td, where d is the amount by which its length has increased from equilibrium.]

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##### ISBN: 9781891389221

The full step-by-step solution to problem: 11.24 from chapter: 11 was answered by , our top Physics solution expert on 09/09/17, 04:12AM. This textbook survival guide was created for the textbook: Classical Mechanics, edition: 0. Since the solution to 11.24 from 11 chapter was answered, more than 348 students have viewed the full step-by-step answer. Classical Mechanics was written by and is associated to the ISBN: 9781891389221. This full solution covers the following key subjects: direction, Small, move, Masses, length. This expansive textbook survival guide covers 16 chapters, and 736 solutions. The answer to “Two equal masses m move on a frictionless horizontal table. They are held by three identical taut strings (each of length L, tension T), as shown in Figure 11.19, so that their equilibrium position is a straight line between the anchors at A and B. The two masses move in the transverse (y) direction, but not in the longitudinal (x) direction. Write down the Lagrangian for small displacements, and find and describe the motion in the corresponding normal modes. [Hint: "Small" displacements have yi and y2 much less than L, which means that you can treat the tensions as constant. Therefore the PE of each string is just Td, where d is the amount by which its length has increased from equilibrium.]” is broken down into a number of easy to follow steps, and 122 words.

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