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Solved: Use resonance forms of the conjugate bases to explain why methanesulfonic acid

Organic Chemistry | 8th Edition | ISBN: 9780321811394 | Authors: L.g. Wade, Jr. ISBN: 9780321811394 460

Solution for problem 11-32 Chapter Chapter 11

Organic Chemistry | 8th Edition

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Organic Chemistry | 8th Edition | ISBN: 9780321811394 | Authors: L.g. Wade, Jr.

Organic Chemistry | 8th Edition

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Problem 11-32

Use resonance forms of the conjugate bases to explain why methanesulfonic acid (CH3SO3H, pKa = -2.6) is a much stronger acid than acetic acid (CH3COOH, pKa = 4.8).

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General Chemistry 2 Notes: Ch. 15  Rules of thumb: Carbon always has 4 bonds Nitrogen typically has 3 bonds Oxygen typically has 2 bonds Halogens typically have 1 bond  Organic Chemistry The study of carbon compounds Mainly concerns carbon bound to hydrogen Other common elements are H, F, N,...

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Chapter Chapter 11, Problem 11-32 is Solved
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Textbook: Organic Chemistry
Edition: 8
Author: L.g. Wade, Jr.
ISBN: 9780321811394

Since the solution to 11-32 from Chapter 11 chapter was answered, more than 234 students have viewed the full step-by-step answer. Organic Chemistry was written by and is associated to the ISBN: 9780321811394. The answer to “Use resonance forms of the conjugate bases to explain why methanesulfonic acid (CH3SO3H, pKa = -2.6) is a much stronger acid than acetic acid (CH3COOH, pKa = 4.8).” is broken down into a number of easy to follow steps, and 28 words. This full solution covers the following key subjects: . This expansive textbook survival guide covers 26 chapters, and 1424 solutions. The full step-by-step solution to problem: 11-32 from chapter: Chapter 11 was answered by , our top Chemistry solution expert on 03/16/18, 03:33PM. This textbook survival guide was created for the textbook: Organic Chemistry, edition: 8.

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Solved: Use resonance forms of the conjugate bases to explain why methanesulfonic acid

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