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Estimate the density of the water 6.0 km deep in the sea.

Physics: Principles with Applications | 6th Edition | ISBN: 9780130606204 | Authors: Douglas C. Giancoli ISBN: 9780130606204 3

Solution for problem 21P Chapter 10

Physics: Principles with Applications | 6th Edition

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Physics: Principles with Applications | 6th Edition | ISBN: 9780130606204 | Authors: Douglas C. Giancoli

Physics: Principles with Applications | 6th Edition

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Problem 21P

Problem 21P

Estimate the density of the water 6.0 km deep in the sea. (See Table 9–1 and Section 9–5 regarding bulk modulus.) By what fraction does it differ from the density at the surface?

TABLE 9–1 Elastic Moduli

Step-by-Step Solution:
Step 1 of 3

ANSWER:STEP 1:-Every ideal spring obeys Hooke’s law. The law tells about the relation between thedisplacement of the spring with the restoring force.The force is, F = Kx-------------------(1)The potential energy whose derivative will give such force is, P.E = 1/2 Kx -----------------(2)Here K is the spring constant and x is the displacement of the spring.STEP 2:-The sprinters stretch 33 mm which is equal to 0.001 × 41 = 0.041 metersThe spring constant given for them is, 33 N/mmAs we know, 1mm = 0.001 m 33 N/mm = 33/0.001 = 33000 N/mSo, K=33000 N/m.The potential energy stored is, P.E = 1/2 Kx = 1/2 × 33000 × 0.041 = 27.73 jules.STEP 3:-The nonathletes stretch 41 mm which is equal to 0.001 × 33 = 0.033 metersThe spring constant given for them is, 33 N/mm\nAs we know, 1mm = 0.001 m 33 N/mm = 33/0.001 = 33000 N/mSo, K=33000 N/m.The potential energy stored is, P.E = 1/2 Kx = 1/2 × 33000 × 0.033 = 17.96 = 18jules (approximately).STEP 4:-The difference between the potential energies is, P.E = 27.73 18 = 9.73 jules.CONCLUSION:The difference between maximum stored energies between the sprinter and nonathletes is9.73 jules.

Step 2 of 3

Chapter 10, Problem 21P is Solved
Step 3 of 3

Textbook: Physics: Principles with Applications
Edition: 6
Author: Douglas C. Giancoli
ISBN: 9780130606204

This full solution covers the following key subjects: Density, Table, Modulus, differ, elastic. This expansive textbook survival guide covers 35 chapters, and 3914 solutions. The answer to “Estimate the density of the water 6.0 km deep in the sea. (See Table 9–1 and Section 9–5 regarding bulk modulus.) By what fraction does it differ from the density at the surface?TABLE 9–1 Elastic Moduli” is broken down into a number of easy to follow steps, and 36 words. Physics: Principles with Applications was written by and is associated to the ISBN: 9780130606204. Since the solution to 21P from 10 chapter was answered, more than 952 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Physics: Principles with Applications, edition: 6. The full step-by-step solution to problem: 21P from chapter: 10 was answered by , our top Physics solution expert on 03/03/17, 03:53PM.

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Estimate the density of the water 6.0 km deep in the sea.