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Answer: Ethylene (C2H4), an important industrial organic

Chapter 3, Problem 92P

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QUESTION:

Ethylene \(\left(\mathrm{C}_{2} \mathrm{H}_{4}\right)\), an important industrial organic chemical, can be prepared by heating hexane \(\left(\mathrm{C}_{6} \mathrm{H}_{14}\right)\) at \(800^{\circ} \mathrm{C}\):

                          \(\mathrm{C}_{6} \mathrm{H}_{14} \longrightarrow \mathrm{C}_{2} \mathrm{H}_{4}+\) other products

If the yield of ethylene production is 42.5 percent, what mass of hexane must be reacted to produce 481 g of ethylene?

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QUESTION:

Ethylene \(\left(\mathrm{C}_{2} \mathrm{H}_{4}\right)\), an important industrial organic chemical, can be prepared by heating hexane \(\left(\mathrm{C}_{6} \mathrm{H}_{14}\right)\) at \(800^{\circ} \mathrm{C}\):

                          \(\mathrm{C}_{6} \mathrm{H}_{14} \longrightarrow \mathrm{C}_{2} \mathrm{H}_{4}+\) other products

If the yield of ethylene production is 42.5 percent, what mass of hexane must be reacted to produce 481 g of ethylene?

ANSWER:

Step 1 of 2

Here we have to calculate mass of hexane required to produce 481 g of ethylene.

The given chemical reaction is,

 + other product

Yield of ethylene = 42.5 %

Mass of ethylene = 481 g

It is known that, the % yield can be calculated as,

% yield =   100 %

We can write this equation as,

42.5 % yield =   100 %

Theoretical yield  = 48142.5%  =  

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