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Using Yates’s Correction for Continuity The chi-square

Chapter 11, Problem 22BB

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QUESTION:

Using Yates's Correction for Continuity The chi-square distribution is continuous, whereas the test statistic used in this section is discrete. Some statisticians use Yates's correction for continuity in cells with an expected frequency of less than 10 or in all cells of a contingency table with two rows and two columns. With Yates's correction, we replace

                  \(\Sigma(O-E) 2 E \text { with } \Sigma(|O-E|-0.5) 2 E\)

Given the contingency table in Example 4, find the value of the \(\chi 2\) test statistic using Yates's correction. What effect does Yates's correction have?

Equation Transcription:

Text Transcription:

\Sigma(O-E) 2 E \text { with } \Sigma(|O-E|-0.5) 2 E

\chi 2

Questions & Answers

QUESTION:

Using Yates's Correction for Continuity The chi-square distribution is continuous, whereas the test statistic used in this section is discrete. Some statisticians use Yates's correction for continuity in cells with an expected frequency of less than 10 or in all cells of a contingency table with two rows and two columns. With Yates's correction, we replace

                  \(\Sigma(O-E) 2 E \text { with } \Sigma(|O-E|-0.5) 2 E\)

Given the contingency table in Example 4, find the value of the \(\chi 2\) test statistic using Yates's correction. What effect does Yates's correction have?

Equation Transcription:

Text Transcription:

\Sigma(O-E) 2 E \text { with } \Sigma(|O-E|-0.5) 2 E

\chi 2

ANSWER:

Solution  22BB

According to the Yates’s correction for continuity, the test statistic is,

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