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Answer: An impure sample of zinc (Zn) is treated with an
Chapter 3, Problem 113P(choose chapter or problem)
An impure sample of zinc \((\mathrm{Zn})\) is treated with an excess of sulfuric acid \(\left(\mathrm{H}_{2} \mathrm{SO}_{4}\right)\) to form zinc sulfate \((\mathrm{ZnSO}_4)\) and molecular hydrogen \((\mathrm{H}_2)\). (a) Write a balanced equation for the reaction. (b) If 0.0764 g of \(\mathrm{H}_2\) is obtained from 3.86 g of the sample, calculate the percent purity of the sample. (c) What assumptions must you make in (b)?
Questions & Answers
QUESTION:
An impure sample of zinc \((\mathrm{Zn})\) is treated with an excess of sulfuric acid \(\left(\mathrm{H}_{2} \mathrm{SO}_{4}\right)\) to form zinc sulfate \((\mathrm{ZnSO}_4)\) and molecular hydrogen \((\mathrm{H}_2)\). (a) Write a balanced equation for the reaction. (b) If 0.0764 g of \(\mathrm{H}_2\) is obtained from 3.86 g of the sample, calculate the percent purity of the sample. (c) What assumptions must you make in (b)?
ANSWER:
Step 1 of 4
Zinc (Zn) is treated with an excess of sulfuric acid () to form zinc sulfate () and molecular hydrogen ().
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