Solved: A force parallel to the x-axis acts on a particle

Chapter 7, Problem 7.35

(choose chapter or problem)

A force parallel to the x-axis acts on a particle moving along the x-axis. This force produces potential energy U(x) given by \(U(x)=\alpha x^{4}\), where \(\\alpha=1.20\mathrm{\ J}/\mathrm{m}^4\). What is the force (magnitude and direction) when the particle is at x = - 0.800 m?

Text Transcription:

U(x) = alpha x^4

alpha = 1.20 J/m^4

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