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Statistics / The Practice of Statistics 5 / Chapter 10.2 / Problem 64

The Practice of Statistics | 5th Edition | ISBN: 9781464108730 | Authors: Daren S. Starnes, Josh Tabor

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. Information online (8.2, 10.1) A random digit dialing sample of 2092 adults found that

Chapter 10, Problem 64

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QUESTION:

. Information online (8.2, 10.1) A random digit dialing sample of 2092 adults found that 1318 used the Internet.42 Of the users, 1041 said that they expect businesses to have Web sites that give product information; 294 of the 774 nonusers said this. (a) Construct and interpret a 95% confidence interval for the proportion of all adults who use the Internet. (b) Construct and interpret a 95% confidence interval to compare the proportions of users and nonusers who expect businesses to have Web sites that give product information.

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QUESTION:

. Information online (8.2, 10.1) A random digit dialing sample of 2092 adults found that 1318 used the Internet.42 Of the users, 1041 said that they expect businesses to have Web sites that give product information; 294 of the 774 nonusers said this. (a) Construct and interpret a 95% confidence interval for the proportion of all adults who use the Internet. (b) Construct and interpret a 95% confidence interval to compare the proportions of users and nonusers who expect businesses to have Web sites that give product information.

ANSWER:

Step 1 of 3

(a)

The sample proportion is the number of successes divided by the sample size:

For confidence level , determine using table II (look up in the table, the z-score is then the found -score with opposite sign):

The margin of error is then:

The confidence interval then becomes:

We are confident that the true proportion of internet users is between and

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