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Get Full Access to Vector Mechanics For Engineers: Statics - 10 Edition - Chapter 5 - Problem 5.112
Get Full Access to Vector Mechanics For Engineers: Statics - 10 Edition - Chapter 5 - Problem 5.112

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An 8-in.-diameter cylindrical duct and a 4 8-in. rectangular duct are to be joined as

ISBN: 9780077402280 491

Solution for problem 5.112 Chapter 5

Vector Mechanics for Engineers: Statics | 10th Edition

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Problem 5.112

An 8-in.-diameter cylindrical duct and a 4 8-in. rectangular duct are to be joined as indicated. Knowing that the ducts were fabricated from the same sheet metal, which is of uniform thickness, locate the center of gravity of the assembly.

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Definition 1.1. Given two integers a and d with d non-zero, we say that d divides a (written d | a) if there is an integer c with a = cd. If no such integer exists, so d does not divide a, we write d - a. If d divides a, we say that d is a divisor of a. Proposition 1.2.1: Assume that a, b, and c are integers. If a | b and b | c, then a | c. Proposition 1.3. Assume that a, b, d, x, and y are integers. If d | a and d | b, then d | ax + by. Corollary 1.4. Assume that a, b, and d are integers. If d | a and d | b, then d | a + b and d | a − b. Proposition 1.4. Let a, b, c ∈ Z be integers. a) If a | b and b | c, then a | c. b) If a | b and b | a, then a = ±b. c) If a | b and a | c, then a | (b + c) and a | (b − c). Prime: A prime number is an integer p ≥ 2 whose only divisors are

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