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For the tower and loading of 6.23 and knowing that FCH = FEJ = 1.2 kN C and FEH = 0

Vector Mechanics for Engineers: Statics | 10th Edition | ISBN: 9780077402280 | Authors: Ferdinand Beer, E. Russell Johnston Jr., David Mazurek ISBN: 9780077402280 491

Solution for problem 6.24 Chapter 6

Vector Mechanics for Engineers: Statics | 10th Edition

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Vector Mechanics for Engineers: Statics | 10th Edition | ISBN: 9780077402280 | Authors: Ferdinand Beer, E. Russell Johnston Jr., David Mazurek

Vector Mechanics for Engineers: Statics | 10th Edition

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Problem 6.24

For the tower and loading of 6.23 and knowing that FCH = FEJ = 1.2 kN C and FEH = 0, determine the force in member HJ and in each of the members located between HJ and NO. State whether each member is in tension or compression. PROBLEM 6.23 The portion of truss shown represents the upper part of a power transmission line tower. For the given loading, determine the force in each of the members located above HJ. State whether each member is in tension or compression.

Step-by-Step Solution:
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Day 10­Binary ­Base ten numbers are decimal numbers ­Binary numbers are base 10 (only 1 and 0, on or off.) ­every binary has a unique decimal value and vice versa ­decimal numbers only have digits from 0­9, and they don’t have to have a decimal in them (ex.33, 493, 39393) ­example, how to get the decimal number 15 is (1x10^1)+(5x10^0) ­the value of a binary number and decimal number are different. If you see a number of only ones or zeroes, you have to be told whether it is decimal or binary ­check the lecture slides for this day Day 11 ­ a breakpoint is a red point that stops to check what is happening ­the for loop is used when you want the calculations to be performed a certain number of times ­the first statement is how many times the statement will be executed

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Chapter 6, Problem 6.24 is Solved
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Textbook: Vector Mechanics for Engineers: Statics
Edition: 10
Author: Ferdinand Beer, E. Russell Johnston Jr., David Mazurek
ISBN: 9780077402280

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For the tower and loading of 6.23 and knowing that FCH = FEJ = 1.2 kN C and FEH = 0