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Chemistry | 11th Edition | ISBN: 9780073402680 | Authors: Raymond Chang
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Answer: Determine how many grams of each of the following

Chapter 4, Problem 68P

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QUESTION:

Determine how many grams of each of the following solutes would be needed to make \(2.50 \times 10^{2}\) mL of a 0.100 M solution: (a) cesium iodide (CsI), (b) sulfuric acid (\(\mathrm{H}_{2} \mathrm{SO}_{4}\)), (c) sodium carbonate (\(\mathrm{Na}_{2} \mathrm{CO}_{3}\)), (d) potassium dichromate (\(\mathrm{~K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\)), (e) potassium permanganate (\(\mathrm{KMnO}_{4}\)).

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QUESTION:

Determine how many grams of each of the following solutes would be needed to make \(2.50 \times 10^{2}\) mL of a 0.100 M solution: (a) cesium iodide (CsI), (b) sulfuric acid (\(\mathrm{H}_{2} \mathrm{SO}_{4}\)), (c) sodium carbonate (\(\mathrm{Na}_{2} \mathrm{CO}_{3}\)), (d) potassium dichromate (\(\mathrm{~K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\)), (e) potassium permanganate (\(\mathrm{KMnO}_{4}\)).

ANSWER:

Step 1 of 7

Here we have to calculate mass in gram of each of the following solutes would be needed to make  mL of a 0.100 M solution.

 

Given :

Volume of solution =  mL or 0. 250 L

Molarity = 0.100M

 

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