Solution Found!
Elevator Safety Exercise 1 uses ? = 182.9 lb, which is
Chapter 6, Problem 12BSC(choose chapter or problem)
Elevator Safety Exercise 11 uses \(\mu 182.9 l b\) , which is based on Data Set 1 in Appendix B. Repeat Exercise 11 using \(\mu 174 l b\) (instead of 182.9 lb), which is the assumed mean weight that was commonly used just a few years ago. Assuming that the mean weight of males is now 182.9 lb, not the value of 174 lb that was used just a few years ago, what do you conclude about the effect of using an outdated mean that is substantially lower than it should be?
Equation Transcription:
Text Transcription:
\mu 182.9 l b
\mu 174 l b
Questions & Answers
QUESTION:
Elevator Safety Exercise 11 uses \(\mu 182.9 l b\) , which is based on Data Set 1 in Appendix B. Repeat Exercise 11 using \(\mu 174 l b\) (instead of 182.9 lb), which is the assumed mean weight that was commonly used just a few years ago. Assuming that the mean weight of males is now 182.9 lb, not the value of 174 lb that was used just a few years ago, what do you conclude about the effect of using an outdated mean that is substantially lower than it should be?
Equation Transcription:
Text Transcription:
\mu 182.9 l b
\mu 174 l b
ANSWER:Answer :
Step 1 of 1 :
Elevator Safety Exercise 1 uses μ = 182.9 lb, which is based on Data Set 1. Repeat Exercise 11 using μ = 174 lb (instead of 182.9 lb), which is the assumed mean weight that was commonly used just a few years ago. Assuming that the mean weight of males is now 182.9 lb, not the value of 174 lb that was used just a few years ago.
By the central limit theorem,the sample mean is normally distributed with mean and standard deviation .
The elevator is loaded with 16 male passengers,a mean weight of up to 195.3 lb.
Here n = 16 and x=195.3