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Answer: A quantity of 18.68 mL of a KOH solution is needed

Chapter 4, Problem 89P

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QUESTION:

A quantity of 18.68 mL of a KOH solution is needed to neutralize 0.4218 g of KHP. What is the concentration (in molarity) of the KOH solution?

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QUESTION:

A quantity of 18.68 mL of a KOH solution is needed to neutralize 0.4218 g of KHP. What is the concentration (in molarity) of the KOH solution?

ANSWER:

Step 1 of 2

 

The goal of the problem is to calculate the concentration (in molarity) of the KOH solution.

Given:

Volume of KOH solution = 18.68 mL = 18.68  L

Mass of KHP = 0.4218 g.

The reaction between KHP () and KOH is:

           

The molarity can be calculated using the formula:

Molarity =  

Let’s first, find the number of moles in KOH using the mass of KHP:

Molar mass of KHP = 204.22 g/mol

The mole ratio of KOH and KHP is 1: 1.

= 0.4218 g KHP

= 2.0654 mol KOH

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