Solution Found!
Answer: A 3.664-g sample of a monoprotic acid was
Chapter 4, Problem 111P(choose chapter or problem)
QUESTION:
A 3.664-g sample of a monoprotic acid was dissolved in water. It took 20.27 mL of a 0.1578 M NaOH solution to neutralize the acid. Calculate the molar mass of the acid.
Questions & Answers
QUESTION:
A 3.664-g sample of a monoprotic acid was dissolved in water. It took 20.27 mL of a 0.1578 M NaOH solution to neutralize the acid. Calculate the molar mass of the acid.
ANSWER:Step 1 of 3
The goal of the problem is to calculate the molar mass of the acid.
Given:
Mass of a monoprotic acid = 3.664 g.
Volume of NaOH = 20.27 mL
Molarity of NaOH = 0.1578 M
The neutralization reaction happening is: