A force F = (3.00 N)i + (7.00 N)] + (7.00 N)k acts on a

Chapter 7, Problem 51

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A force F = (3.00 N)i + (7.00 N)] + (7.00 N)k acts on a 2.00 kg mobile object that moves from an initial position of d; = (3.00 m)i - (2.00 m)] + (5.00 m)k to a final position of df = -(5.00 m)i + (4.00 m)] + (7.00 m)k in 4.00 s. Find (a) the work done on the object by the force in the 4.00 s interval, (b) the average power due to the force during that interval, and (c) the angle between vectors d; and df .

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