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Solved: Relative Frequencies for Comparisons.Construct the

Elementary Statistics | 12th Edition | ISBN: 9780321836960 | Authors: Mario F. Triola ISBN: 9780321836960 18

Solution for problem 16BSC Chapter 2.2

Elementary Statistics | 12th Edition

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Elementary Statistics | 12th Edition | ISBN: 9780321836960 | Authors: Mario F. Triola

Elementary Statistics | 12th Edition

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Problem 16BSC

 

Relative Frequencies for Comparisons.Construct the relative frequencies and answer the given questions.

White Blood Cell Counts Construct one table (similar to Table) that includes relative frequencies based on the frequency distributions from Exercises 1 and 2, and then compare the white blood cell counts of females and males. Are there notable differences?

Table

IQ Scores from the Low Lead Group and the High Lead Group

Exercise

Exercise 1

identify the class width, class midpoints, and class boundaries for the given frequency distribution. The frequency distributions are based on real data from Appendix B.

Exercise 2

identify the class width, class midpoints, and class boundaries for the given frequency distribution. The frequency distributions are based on real data from Appendix B.

Step-by-Step Solution:

Answer :

Step 1 of 2 :

Given, White blood cell count of males and the frequency

White blood cell count of males

Frequency

3 - 4.9

8

5 - 6.9

15

7 - 8.9

11

9 - 10.9

5

11 - 12.9

1

We have to find the relative frequency for comparison

The total frequency = 82

Relative frequency =

Example :

               Relative frequency =

                                               = 20

class width : the difference between the upper and lower class limit.

Example : 4.9 - 3

                  = 1.9

class midpoints : (lower class limit + upper class limit)/ 2 

Example : (3+4.9)/2

              = 3.95

 class boundaries :

Upper class boundary = Upper limit + ()  unit of measurement

Ex: 4.9 is the upper class limit and unit of measurement is 0.1

Therefore ,

Upper class boundary = 4.9 + ()  0.1

                                    = 4.95

Lower class boundary = Lower limit + ()  unit of measurement

Ex: 4.9 is the upper class limit and unit of measurement is 0.1

Therefore ,

Upper class boundary = 3 + ()  0.1

                                    = 3.05

White blood cell count of males

Frequency

Relative frequency

Class width

Class midpoints

Class boundaries

3 - 4.9

8

20

1.9

3.95

(3.05 , 4.95)

5 - 6.9

15

37.5

1.9

5.95

(5.05 , 6.95)

7 - 8.9

11

27.5

1.9

7.95

(7.05 , 8.95)

9 - 10.9

5

12.5

1.9

9.95

(9.05 , 10.95)

11 - 12.9

1

2.5

1.9

11.95

(11.05 , 12.95)

Step 2 of 2

Chapter 2.2, Problem 16BSC is Solved
Textbook: Elementary Statistics
Edition: 12
Author: Mario F. Triola
ISBN: 9780321836960

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