×
Get Full Access to Elementary Statistics - 12 Edition - Chapter 2.2 - Problem 16bsc
Get Full Access to Elementary Statistics - 12 Edition - Chapter 2.2 - Problem 16bsc

×

# Solved: Relative Frequencies for Comparisons.Construct the ISBN: 9780321836960 18

## Solution for problem 16BSC Chapter 2.2

Elementary Statistics | 12th Edition

• Textbook Solutions
• 2901 Step-by-step solutions solved by professors and subject experts
• Get 24/7 help from StudySoup virtual teaching assistants Elementary Statistics | 12th Edition

4 5 1 425 Reviews
21
0
Problem 16BSC

Relative Frequencies for Comparisons.Construct the relative frequencies and answer the given questions.

White Blood Cell Counts Construct one table (similar to Table) that includes relative frequencies based on the frequency distributions from Exercises 1 and 2, and then compare the white blood cell counts of females and males. Are there notable differences?

Table

IQ Scores from the Low Lead Group and the High Lead Group Exercise

Exercise 1

identify the class width, class midpoints, and class boundaries for the given frequency distribution. The frequency distributions are based on real data from Appendix B. Exercise 2

identify the class width, class midpoints, and class boundaries for the given frequency distribution. The frequency distributions are based on real data from Appendix B. Step-by-Step Solution:

Step 1 of 2 :

Given, White blood cell count of males and the frequency

 White blood cell count of males Frequency 3 - 4.9 8 5 - 6.9 15 7 - 8.9 11 9 - 10.9 5 11 - 12.9 1

We have to find the relative frequency for comparison

The total frequency = 82

Relative frequency = Example :

Relative frequency = = 20

class width : the difference between the upper and lower class limit.

Example : 4.9 - 3

= 1.9

class midpoints : (lower class limit + upper class limit)/ 2

Example : (3+4.9)/2

= 3.95

class boundaries :

Upper class boundary = Upper limit + ( )  unit of measurement

Ex: 4.9 is the upper class limit and unit of measurement is 0.1

Therefore ,

Upper class boundary = 4.9 + ( )  0.1

= 4.95

Lower class boundary = Lower limit + ( )  unit of measurement

Ex: 4.9 is the upper class limit and unit of measurement is 0.1

Therefore ,

Upper class boundary = 3 + ( )  0.1

= 3.05

 White blood cell count of males Frequency Relative frequency Class width Class midpoints Class boundaries 3 - 4.9 8 20 1.9 3.95 (3.05 , 4.95) 5 - 6.9 15 37.5 1.9 5.95 (5.05 , 6.95) 7 - 8.9 11 27.5 1.9 7.95 (7.05 , 8.95) 9 - 10.9 5 12.5 1.9 9.95 (9.05 , 10.95) 11 - 12.9 1 2.5 1.9 11.95 (11.05 , 12.95)

Step 2 of 2

##### ISBN: 9780321836960

Unlock Textbook Solution