Answer: A 2.10-L vessel contains 4.65 g of a gas at 1.00

Step 1 of 2

Given:

\(\begin{aligned}&\mathrm{T}=27.0^{\circ} \mathrm{C}=27+273=300 \mathrm{~K} \\ &\mathrm{~V}=2.10 \mathrm{~L}\end{aligned}\)

Mass of gas \(=4.65 \mathrm{~g}\)

\(\mathrm{P}=1.00 \mathrm{~atm} .\)

(a) Here, we are asked to calculate the density of the gas in grams per liter:

The formula of density is as shown below:

\(\begin{aligned}\text { Density }(\mathrm{d})=& \frac{\operatorname{mass}(\mathrm{m})}{\operatorname{Volume}(\mathrm{V})} \\&=\frac{4.65 \mathrm{~g}}{2.10 \mathrm{~L}} \\&=\mathbf{2 . 2 1 4} \mathbf{g} / \mathrm{L}\end{aligned}\)

Hence, the density of the gas is \(2.214 \mathrm{~L}\)