Solution Found!

Answer: A mixture of gases contains 0.31 mol CH4, 0.25 mol

Chapter 5, Problem 67P

(choose chapter or problem)

Get Unlimited Answers
QUESTION:

A mixture of gases contains \(0.31\) mol \(\mathrm{CH}_{4}, 0.25\) mol \(\mathrm{C}_{2} \mathrm{H}_{6}\), and \(0.29\) mol \(\mathrm{C}_{3} \mathrm{H}_{8}\). The total pressure is \(1.50 \mathrm{~atm}\). Calculate the partial pressures of the gases.

Questions & Answers

QUESTION:

A mixture of gases contains \(0.31\) mol \(\mathrm{CH}_{4}, 0.25\) mol \(\mathrm{C}_{2} \mathrm{H}_{6}\), and \(0.29\) mol \(\mathrm{C}_{3} \mathrm{H}_{8}\). The total pressure is \(1.50 \mathrm{~atm}\). Calculate the partial pressures of the gases.

ANSWER:

Step 1 of 3

The goal of the problem is to calculate the partial pressures of the gases.

Given:

Number of moles of \(\mathrm{CH}_{4}=0.31 \mathrm{~mol}\)

Number of moles of \(\mathrm{C}_{2} \mathrm{H}_{6}=0.25 \mathrm{~mol}\)

Number of moles of \(\mathrm{C}_{3} \mathrm{H}_{8}=0.29 \mathrm{~mol}\)

The total pressure of gases \(=1.50 \mathrm{~atm}\).

Add to cart


Study Tools You Might Need

Not The Solution You Need? Search for Your Answer Here:

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back