The zirconium oxalate K2Zr(C2O4)3(H2C2O4) H2O was
Chapter 3, Problem 3.127(choose chapter or problem)
The zirconium oxalate K2Zr(C2O4)3(H2C2O4) H2O was synthesized by mixing 1.68 g of ZrOCl2 8H2O with 5.20 g of H2C2O4 2H2O and an excess of aqueous KOH. After 2 months, 1.25 g of crystalline product was obtained, as well as aqueous KCl and water. Calculate the percent yield.
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer