×
Get Full Access to Calculus: Early Transcendentals - 1 Edition - Chapter 1.1 - Problem 28e
Get Full Access to Calculus: Early Transcendentals - 1 Edition - Chapter 1.1 - Problem 28e

×

# Solved: Composite functions and notation. Let f (x)=x -4, ISBN: 9780321570567 2

## Solution for problem 28E Chapter 1.1

Calculus: Early Transcendentals | 1st Edition

• Textbook Solutions
• 2901 Step-by-step solutions solved by professors and subject experts
• Get 24/7 help from StudySoup virtual teaching assistants Calculus: Early Transcendentals | 1st Edition

4 5 1 288 Reviews
18
1
Problem 28E

Composite functions and notation. Let ?f? (x)?=x -4, ?g? (x)=x and ?F(x)=1? /(x-3). Simplify or evaluate the following expressions. f(2+h)?f(2) h

Step-by-Step Solution:

Step by step solution Step 1 of 1 2 3 Consider three different functions f(x)=x -4 (x)=x and F(x)= 1/(x-3). f(2+h)f(2) For evaluating the value of h first find the values of f(2+h)and f(2). If we want to find the values of fu nction (x)for =2+h and x =2 we must use these values in the relation for the f unction (x).This is very easy, just follow the next steps: 2 f(x) = x 4 2 f(2+h) = (2+h) 4 f(2) = 2 4 = 44 = 0 f(2+h)f(2) Now we use the values for f(2+h)and f(2)in order to calculate h : f(2+h)f(2) (2+h) 40 h = h (2+h) 4 = h 2 2 2 Based on the relation (a+b) = a +2ab+b we can write the following: 2 f(2+h)f(2)= (2+h) 4 h h = 2 +2·2h+h 4 h = 4+4h+h 4 2 = 4h+h h = h(h+4) h = 4+h f(2+h)f(2) So the final value of function h is +4.

Step 2 of 1

##### ISBN: 9780321570567

Unlock Textbook Solution