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Calculating Rope Tension from a Central Hanging Weight: A Physics Appr
Chapter 12, Problem 5(choose chapter or problem)
A rope of negligible mass is stretched horizontally between two supports that are 3.44 m apart. When an object of weight 3160 N is hung at the center of the rope, the rope is observed to sag by 35.0 cm. What is the tension in the rope?
Questions & Answers
QUESTION:
A rope of negligible mass is stretched horizontally between two supports that are 3.44 m apart. When an object of weight 3160 N is hung at the center of the rope, the rope is observed to sag by 35.0 cm. What is the tension in the rope?
ANSWER:Step 1 of 3
Consider the given data as follows.
The distance between two supports is L = 3.44 m.
The weight of an object is W = 3160 N.
The distance between the rope and the sag is x = 35.0 cm = 0.35 m.
Draw the free-body diagram as follows.
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Calculating Rope Tension from a Central Hanging Weight: A Physics Appr
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Discover how to calculate rope tension with an object hanging in the center. Understand the relationship between the sag, the weight of the object, and the tension. Convert the result into kilonewtons for easy reference.