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Get Full Access to Chemistry: The Central Science - 14 Edition - Chapter 14 - Problem 14.27
Get Full Access to Chemistry: The Central Science - 14 Edition - Chapter 14 - Problem 14.27

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# ?A reaction $$\mathrm{A}+\mathrm{B} \longrightarrow \mathrm{C}$$ obeys the following rate law: Rate = $$k[\mathrm{~B}]^{2}$$. (a) If [A] is d ISBN: 9780134414232 1274

## Solution for problem 14.27 Chapter 14

Chemistry: The Central Science | 14th Edition

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Problem 14.27

A reaction $$\mathrm{A}+\mathrm{B} \longrightarrow \mathrm{C}$$ obeys the following rate law: Rate = $$k[\mathrm{~B}]^{2}$$.

(a) If [A] is doubled, how will the rate change? Will the rate constant change?

(b) What are the reaction orders for A and B? What is the overall reaction order?

(c) What are the units of the rate constant?

Text Transcription:

A + B \longrightarrow C

k[B]^ 2

Step-by-Step Solution:

Step 1 of 5) Although N2, O2, and atomic oxygen absorb photons having wavelengths shorter than 240 nm, ozone, O3, is the key absorber of photons whose wavelengths range from 240 to 310 nm, in the ultraviolet region of the electromagnetic spectrum, as illustrated in Figure 18.4. Ozone in the upper atmosphere protects us from these harmful high-energy photons, which would otherwise penetrate to Earth’s surface. Let’s consider how ozone forms in the upper atmosphere and how it absorbs photons. By the time radiation from the Sun reaches an altitude of 90 km above Earth’s surface, most of the short-wavelength radiation capable of photoionization has been absorbed. Nevertheless, radiation capable of dissociating the O2 molecule is sufficiently intense for photodissociation of O2 (Equation 18.1) to remain important down to an altitude of 30 km. In the region between 30 and 90 km, the concentration of O2 is much greater than the concentration of atomic oxygen. Consequently, the oxygen atoms formed by photodissociation of O2 in this region frequently collide with O2 molecules and form ozone:

Step 2 of 2

##### ISBN: 9780134414232

Chemistry: The Central Science was written by and is associated to the ISBN: 9780134414232. This textbook survival guide was created for the textbook: Chemistry: The Central Science, edition: 14. This full solution covers the following key subjects: . This expansive textbook survival guide covers 29 chapters, and 2820 solutions. The answer to “?A reaction $$\mathrm{A}+\mathrm{B} \longrightarrow \mathrm{C}$$ obeys the following rate law: Rate = $$k[\mathrm{~B}]^{2}$$. (a) If [A] is doubled, how will the rate change? Will the rate constant change? (b) What are the reaction orders for A and B? What is the overall reaction order? (c) What are the units of the rate constant?Text Transcription:A + B \longrightarrow Ck[B]^ 2” is broken down into a number of easy to follow steps, and 59 words. Since the solution to 14.27 from 14 chapter was answered, more than 213 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 14.27 from chapter: 14 was answered by , our top Chemistry solution expert on 10/03/18, 06:29PM.

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?A reaction $$\mathrm{A}+\mathrm{B} \longrightarrow \mathrm{C}$$ obeys the following rate law: Rate = $$k[\mathrm{~B}]^{2}$$. (a) If [A] is d