?The reaction between ethyl bromide \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br}\right)\) and hydroxide ion in ethyl alcohol at 330 K, \(\mathrm{C

Chapter 14, Problem 14.32

(choose chapter or problem)

The reaction between ethyl bromide \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br}\right)\) and hydroxide ion in ethyl alcohol at 330 K, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br}(\text { alc })+\mathrm{OH}^{-}(\text {alc }) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(l)+\mathrm{Br}^{-}(\text {alc })\), is first order each in ethyl bromide and hydroxide ion. When \(\left[\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br}\right]\) is 0.0477 M and \(\left[\mathrm{OH}^{-}\right]\) is 0.100 M, the rate of disappearance of ethyl bromide is \(1.7 \times 10^{-7} \mathrm{M} / \mathrm{s}\).

(a) What is the value of the rate constant?

(b) What are the units of the rate constant?

(c) How would the rate of disappearance of ethyl bromide change if the solution were diluted by adding an equal volume of pure ethyl alcohol to the solution?

Text Transcription:

(C_2H_5Br)

C_2H_5Br(alc) + OH- (alc) \longrightarrow C_2H_5OH(l) + Br - (alc)

[C_2H_5Br]

[OH- ]

1.7 X 10-7 M/s

Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.

Becoming a subscriber
Or look for another answer

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back