?For the following exercises, solve f(x) = 0 using the iteration \(x_{n+1}=x_{n}-c
Chapter 4, Problem 411(choose chapter or problem)
For the following exercises, solve f(x) = 0 using the iteration \(x_{n+1}=x_{n}-c f\left(x_{n}\right)\), which differs slightly from Newton’s method. Find a c that works and a c that fails to converge, with the exception of c = 0.
\(f(x)=x^{2}-4\), with \(x_{0}=0\)
Text Transcription:
x_n+1=x_n -cf(x_n)
f(x)=x^2-4
x_0=0
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