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Get Full Access to Statistics: Informed Decisions Using Data - 5 Edition - Chapter 10 - Problem 11
Get Full Access to Statistics: Informed Decisions Using Data - 5 Edition - Chapter 10 - Problem 11

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# ?Sneeze According to work done by Nick Wilson of Otago University Wellington, the proportion of individuals who cover their mouth when sneezing is 0.73

ISBN: 9780134133539 240

## Solution for problem 11 Chapter 10

Statistics: Informed Decisions Using Data | 5th Edition

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Problem 11

Sneeze According to work done by Nick Wilson of Otago University Wellington, the proportion of individuals who cover their mouth when sneezing is 0.733. As part of a school project, Mary decides to confirm this by observing 100 randomly selected individuals sneeze and finds that 78 covered their mouth when sneezing.

(a) What are the null and alternative hypotheses for Mary’s Project?

(b) Verify the requirements that allow use of the normal model to test the hypothesis are satisfied.

(c) Does the sample evidence contradict Professor Wilson’s findings?

Step-by-Step Solution:

Step 1 of 5) Sneeze According to work done by Nick Wilson of Otago University Wellington, the proportion of individuals who cover their mouth when sneezing is 0.733. As part of a school project, Mary decides to confirm this by observing 100 randomly selected individuals sneezing and finds that 78 covered their mouths when sneezing. (a) What are the null and alternative hypotheses for Mary’s Project (b) Verify the requirements that allow the use of the normal model to test the hypothesis are satisfied. (c) Does the sample evidence contradict Professor Wilson’s findings Apply the Rules of Probabilities In the following probability rules, the notation P1E2 means “the probability that event E occurs.” Rules of Probabilities 1. The probability of any event E, P(E), must be greater than or equal to 0 and less than or equal to 1. That is, 0 … P1E2 … 1. 2. The sum of the probabilities of all outcomes must equal 1. That is, if the sample space S = 5e1, e2, g, en6, then P1e12 + P1e22 + g+ P1en2 = 1

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