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Limits of sequences Evaluate the limit of the | Ch 8 - 9RE

Calculus: Early Transcendentals | 1st Edition | ISBN: 9780321570567 | Authors: William L. Briggs, Lyle Cochran, Bernard Gillett ISBN: 9780321570567 2

Solution for problem 9RE Chapter 8

Calculus: Early Transcendentals | 1st Edition

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Calculus: Early Transcendentals | 1st Edition | ISBN: 9780321570567 | Authors: William L. Briggs, Lyle Cochran, Bernard Gillett

Calculus: Early Transcendentals | 1st Edition

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Problem 9RE

Limits of sequences Evaluate the limit of the sequence or state that it does not exist.

Step-by-Step Solution:
Step 1 of 3

STEP_BY_STEP SOLUTION Step-1 Definition ; A series is said to be convergent if it approaches some limit .Formally , the infinite series a n is convergent if the sequence of partial sums n=1 n S n a k is convergent . Conversely , a series is divergent if the k=1sequence ofpartial sums is divergent.NOTE : The terms grow without bound , so the sequence does not converge. If U k and V k are convergent series , then ( U + Vk k ) and ( U - V k k ) areconvergent . If C = / 0 , then U k and V k both converge or both diverge . Step-2 (1) 1 nThe given sequence is a = n n = ( 0.9 (0.9) n = ( 10) , since 0.9 = 9 9 10 = ( 1) ( ) 10 n …………….(1) 9 10 10 n Here , 9 >1 . So , as n , then the value of ( ) 9 also tending to infinity. From the step (1) , we know that , The terms grow without bound , so the sequence does notconverge. n (1) n 10 n Therefore , lna =nlim n (0.9) = lin 1) ( ) 9 , since from (1).\n Therefore , the given sequence does not converge , since as n ,the termsgrow without bound . (1)n Therefore , lim a = lnm n does not converge. n n (0.9)

Step 2 of 3

Chapter 8, Problem 9RE is Solved
Step 3 of 3

Textbook: Calculus: Early Transcendentals
Edition: 1
Author: William L. Briggs, Lyle Cochran, Bernard Gillett
ISBN: 9780321570567

This full solution covers the following key subjects: evaluate, exist, Limit, Limits, sequence. This expansive textbook survival guide covers 85 chapters, and 5218 solutions. The answer to “Limits of sequences Evaluate the limit of the sequence or state that it does not exist.” is broken down into a number of easy to follow steps, and 16 words. The full step-by-step solution to problem: 9RE from chapter: 8 was answered by , our top Calculus solution expert on 03/03/17, 03:45PM. Since the solution to 9RE from 8 chapter was answered, more than 342 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Calculus: Early Transcendentals, edition: 1. Calculus: Early Transcendentals was written by and is associated to the ISBN: 9780321570567.

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Limits of sequences Evaluate the limit of the | Ch 8 - 9RE