?If \(\theta_{\mathrm{b}}\) is Brewster’s angle for light reflected from the top of an

Chapter 1, Problem 84

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If \(\theta_{\mathrm{b}}\) is Brewster’s angle for light reflected from the top of an interface between two substances, and \(\theta_{\mathrm{b}}^{\prime}\) is Brewster’s angle for light reflected from below, prove that \(\theta_{\mathrm{b}}+\theta_{\mathrm{b}}^{\prime}=90.0^{\circ}\).

 

Text Transcription:

theta_b

theta_b’

Theta_b+theta b’=90.0 degrees

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