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Get Full Access to University Physics, Volume 3 - 17 Edition - Chapter 7 - Problem 63
Get Full Access to University Physics, Volume 3 - 17 Edition - Chapter 7 - Problem 63

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ISBN: 9781938168185 2032

## Solution for problem 63 Chapter 7

University Physics, Volume 3 | 17th Edition

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Problem 63

The Quantum Harmonic Oscillator

A particle with mass 0.030 kg oscillates back and-forth on a spring with frequency 4.0 Hz. At the equilibrium position, it has a speed of 0.60 m/s. If the particle is in a state of definite energy, find its energy quantum number.

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Ch. 5 Free Energy and Chemical Thermodynamics 5.1 Free Energy Enthalpy: H=U+PV Helmholtz free energy: F=U−TS G=U−TS+PV=H−TS Gibbs free energy: 1. T=constant F=U−TS ∆ F=∆U−T ∆ S ∆ U=Q+W ∆ F≤W 2. T=constant ,P=constant G=U−TS+PV ∆ G=∆U−T ∆S+P ∆V→∆ U=Q+W Q−T ∆S≤0,W=−PdV+W other →∆G=Q−T ∆ S+W other ∆ G≤W other * W otheis not due to volume change, but something like electrical work. 3. Fuel Cells & Batteries 1 H2O→ O +H2 2 2 1 ∆ H= (2H) +(∆O2) −(∆HH2 H2O ∆ H=0+0− −285.83kJ )=285.83kJ To make room for H an2 O , en2rgy is: 5 −3 3 1 −3 3 PdV= (10 Pa )[2.45L∗10 m + 2(24.5∗10 m )]≈−4kJ ∆ U=∆ H+P∆ V=286kJ−4 kJ=282 kJ

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