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Get Full Access to Chemistry: The Central Science - 14 Edition - Chapter 22 - Problem 22.17
Get Full Access to Chemistry: The Central Science - 14 Edition - Chapter 22 - Problem 22.17

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# ?Complete and balance the following equations: (a) $$\mathrm{NaOCH}_{3}(s)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow$$ (b) $$\math ISBN: 9780134414232 1274 ## Solution for problem 22.17 Chapter 22 Chemistry: The Central Science | 14th Edition • Textbook Solutions • 2901 Step-by-step solutions solved by professors and subject experts • Get 24/7 help from StudySoup virtual teaching assistants Chemistry: The Central Science | 14th Edition 4 5 1 269 Reviews 30 0 Problem 22.17 Complete and balance the following equations: (a) \(\mathrm{NaOCH}_{3}(s)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow$$

(b) $$\mathrm{CuO}(s)+\mathrm{HNO}_{3}(a q) \longrightarrow$$

(c) $$\mathrm{WO}_{3}(s)+\mathrm{H}_{2}(g) \stackrel{\Delta}{\longrightarrow}$$

(d) $$\mathrm{NH}_{2} \mathrm{OH}(l)+\mathrm{O}_{2}(g) \longrightarrow$$

(e) $$\mathrm{Al}_{4} \mathrm{C}_{3}(s)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow$$

Text Transcription:

NaOCH3(s) + H2O(l) \longrightarrow

CuO1s2 + HNO3(aq) \longrightarrow

WO3(s) + H2(g) \stackrel \Delta \longrightarrow

NH2OH(l) + O2(g) \longrightarrow

Al4C3(s) + H2O(l) \longrightarrow

Step-by-Step Solution:

Step 1 of 5) The trend from non metallic to metallic character as we go down a family is strikingly evident in group 4A. Carbon is a nonmetal; silicon and germanium are metalloids; tin and lead are metals. In this section, we consider a few general characteristics of group 4A and then look more thoroughly at silicon. General Characteristics of the Group 4A Elements The group 4A elements possess the outer-shell electron configuration ns2np2. The electronegativities of the elements are generally low (Table 22.8); carbides that formally contain C4 - ions are observed only in the case of a few compounds of carbon with very active metals. Formation of 4+ ions by electron loss is not observed for any of these elements; the ionization energies are too high. The +4 oxidation state is common, however, and is found in the vast majority of the compounds of the group 4A elements. The +2 oxidation state is found in the chemistry of germanium, tin, and lead, however, and it is the principal oxidation state for lead. Carbon usually forms a maximum of four bonds. The other members of the family are able to form more than four bonds. (Section 8.7).

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?Complete and balance the following equations: (a) $$\mathrm{NaOCH}_{3}(s)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow$$ (b) \(\math