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Chemistry: The Central Science | 14th Edition | ISBN: 9780134414232 | Authors: Theodore E. Brown; H. Eugene LeMay; Bruce E. Bursten; Catherine Murphy; Patrick Woodward; Matthew E. Stoltzfus ISBN: 9780134414232 1274

Solution for problem 24.3 Chapter 24

Chemistry: The Central Science | 14th Edition

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Chemistry: The Central Science | 14th Edition | ISBN: 9780134414232 | Authors: Theodore E. Brown; H. Eugene LeMay; Bruce E. Bursten; Catherine Murphy; Patrick Woodward; Matthew E. Stoltzfus

Chemistry: The Central Science | 14th Edition

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Problem 24.3

(a) Which of these molecules most readily undergoes an addition reaction?

(b) Which of these molecules is aromatic?

(c) Which of these molecules most readily undergoes a substitution reaction? [Section 24.3]

Step-by-Step Solution:
Step 1 of 3

R=clockwise S=counterclockwise *for a tetrahedral 3D stereoformula -never two lines 180˚ -never all wedges -never all dashes Chiral=not superimposable Achiral=superimposable;if a molecule has a plane of symmetry and is superimposable *NOTE:be able to determine if the structure is R or S *NOTE:meso=more than one chirality center but achiral overall Optical activity=ability of a chiral substance to rotate plane-polarized light (ppl) -measured by a polarimeter l=levorotatory=counterclockwise rotation of ppl (-) d=dextrorotatory=clockwise rotation of ppl (+) =observed angle of rotation Specific rotation=physical property of a chiral compound Optically pure/homochiral/enantiomers=only one pure enantiomer in the sample racemic mixture=50% (-) enantiomer and 50% (+) enantiomer;optically impure *NOTE:The R-enantiomers can be (+) or (-) and then whatever R is,S will be the opposite sign. Cahn-Ingold-Prelog Rules for R,S Notation 1. Higher atomic mass takes precedence 2. Find point of first difference 3. Work outward from point of attachment 4. Evaluate substituent atoms one-by-one 5. Multiply bonded is considered a replicated substituent Fischer Projections=horizontal lines are wedges and vertical lines are dashed wedges Carbohydrates=Cn(H20)n glycerol (glycerin) = OlderTerminology D=(+) L=(-) *NOTE:memorize aldoses on slide 4-14 Epimers=stereoisomers with more than one chiral center and the configuration of o

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Chapter 24, Problem 24.3 is Solved
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Textbook: Chemistry: The Central Science
Edition: 14
Author: Theodore E. Brown; H. Eugene LeMay; Bruce E. Bursten; Catherine Murphy; Patrick Woodward; Matthew E. Stoltzfus
ISBN: 9780134414232

The answer to “?(a) Which of these molecules most readily undergoes an addition reaction? (b) Which of these molecules is aromatic? (c) Which of these molecules most readily undergoes a substitution reaction? [Section 24.3]” is broken down into a number of easy to follow steps, and 31 words. This textbook survival guide was created for the textbook: Chemistry: The Central Science, edition: 14. Chemistry: The Central Science was written by and is associated to the ISBN: 9780134414232. The full step-by-step solution to problem: 24.3 from chapter: 24 was answered by , our top Chemistry solution expert on 10/03/18, 06:29PM. Since the solution to 24.3 from 24 chapter was answered, more than 204 students have viewed the full step-by-step answer. This full solution covers the following key subjects: . This expansive textbook survival guide covers 29 chapters, and 2820 solutions.

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